Question

我很困惑如何在laravel中存储唯一值我想只存储单值transaction_id，那里不应该有多个值。请建议。

            $payment                     = new Payment;
            $payment->order_id           = Input::get('orderid');
            $payment->amount             = (Input::get('base_amount', 0))?Input::get('base_amount'):Input::get('amount');
            $payment->transaction_id     = Input::get('transact');

            how to check if this $payment->transaction_id already exists should not save more than one

            i tried 

            $payment = Payment::where('transaction_id', '=', Input::get('transaction_id'))->first();
            if ($payment === null) {
               $payment->save();
            }

Answer 1

您可以使用请求验证：

public function rules()
{
    return [
        'transaction_id' => 'unique'
    ];
}

如果使用此方法，则应使用php artisan make:request MyRequest命令创建新的Request类。然后将rules()放入创建的MyRequest中，然后您可以在RESTful控制器内部使用它来存储/更新操作（函数）：

public function store(MyRequest $request)
{
    dd($request->all());
}

https://laravel.com/docs/5.2/validation

此外，您可以在模型中使用验证：

private $rules = [
    'transaction_id' => 'required'
    ];

transid应该是laravel check中的唯一商店（价值transid应该是单店）

1 个答案: