Question

我已经设置了一个tableView，其中包含一个搜索栏和一个股票名称列表。我在我的Detail View Controller中插入了一些代码，以便让单元格推送到它并在标签中说出一些内容。问题是每当我点击一个单元格时它会显示另一个单元格。是否有更好或更有效的方式推送到detail View？

以下是代码：

import UIKit

class TableViewLemon: UITableViewController, UISearchResultsUpdating {

let tableData = ["Apple","Google","Facebook","Amazon","Exxon Mobil"]
var filteredTableData = [String]()
var resultSearchController = UISearchController()


override func viewDidLoad() {
    super.viewDidLoad()

    self.resultSearchController = ({
        let controller = UISearchController(searchResultsController: nil)
        controller.searchResultsUpdater = self
        controller.dimsBackgroundDuringPresentation = false
        controller.searchBar.sizeToFit()

        self.tableView.tableHeaderView = controller.searchBar

        return controller
    })()

    // Reload the table
    self.tableView.reloadData()
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

// MARK: - Table view data source

override func numberOfSectionsInTableView(tableView: UITableView) -> Int {
    // 1
    // Return the number of sections.
    return 1
}

override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    // 2
    if (self.resultSearchController.active) {
        return self.filteredTableData.count
    }
    else {
        return self.tableData.count
    }
}

override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCellWithIdentifier("Cell", forIndexPath: indexPath) 

    // 3
    if (self.resultSearchController.active) {
        cell.textLabel?.text = filteredTableData[indexPath.row]

        return cell
    }
    else {
        cell.textLabel?.text = tableData[indexPath.row]

        return cell
    }
}

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    if (segue.identifier == "DetailView") {

        let VC = segue.destinationViewController as! DetailViewLemon

        if let indexPath = self.tableView.indexPathForSelectedRow{

            let Make = tableData[indexPath.row] as String

            VC.sentData1 = Make
        }
    }
}

func updateSearchResultsForSearchController(searchController: UISearchController)
{
    filteredTableData.removeAll(keepCapacity: false)

    let searchPredicate = NSPredicate(format: "SELF CONTAINS[c] %@", searchController.searchBar.text!)
    let array = (tableData as NSArray).filteredArrayUsingPredicate(searchPredicate)
    filteredTableData = array as! [String]

    self.tableView.reloadData()
}
}

Answer 1

我希望您的prepareForSegue能够以filteredTableData的方式区分tableData和cellForRowAtIndexPath。有点像：

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    if (segue.identifier == "DetailView") {
        let VC = segue.destinationViewController as! DetailViewLemon
        if let indexPath = self.tableView.indexPathForSelectedRow {
            let Make = self.resultSearchController.active ? 
                filteredTableData[indexPath.row] as String  : 
                tableData[indexPath.row] as String
            VC.sentData1 = Make
        }
    }
}

顺便说一句，我会避免使用segue.identifier，因为它容易出错（即如果你弄错了没有编译错误）。相反，您可以在目标VC上使用if-let。

而不是：

    if (segue.identifier == "DetailView") {
        let VC = segue.destinationViewController as! DetailViewLemon
        ...
    }

使用：

    if let VC = segue.destinationViewController as? DetailViewLemon {
        ...
    }

推动细节视图

1 个答案: