Question

我有2个列表：（list1，list2）我需要将这些列表合并到另一个列表中，该列表按此顺序包含list1和list2：

listNew = [list1（i），list2（i），list1（i + 1），list2（i + 1），...]

我试过了：

listNew = list1 + list2    
for i in listNew:
    listNew.append(i)
    hranyNew.append(pocetHran/2+i)

但是有一个错误说：

+：＆＃39; int＆＃39;不支持的操作数类型和＆＃39; str＆＃39;

另一个问题是，如何将listNew[i]和listNew[i+1]与listNew[i+2]和listNew[i+3]进行比较？

换句话说，我需要将所有相邻对与pair+1，2等进行比较。谢谢！

Answer 1

我想指出非常方便的itertools.chain()：

SITE    DATE    INDIV   CATEGORY    BIOMASS LENGTH
GC  Oct A   aqu 0.0002  10
GC  Oct A   n/a 0   0
GC  Oct A   terr    0   0
GC  Oct B   aqu 0   0
GC  Oct B   n/a 0   0
GC  Oct B   terr    0   0
GC  Oct C   aqu 0.1875  20
GC  Oct C   n/a 0   0
GC  Oct C   terr    0.5424  30
GC  Aug D   aqu 7.4888  10
GC  Aug D   n/a 0   0
GC  Aug D   terr    100.9245    5
GC  Aug E   aqu 0.0001  1
GC  Aug E   n/a 0   0
GC  Aug E   terr    0   0
GC  Aug F   aqu 0   0
GC  Aug F   n/a 0   0
GC  Aug F   terr    20.593  10
NSVhi   Oct A   aqu 5.8713  5
NSVhi   Oct A   n/a 0   0
NSVhi   Oct A   terr    13.8651 3
NSVhi   Oct B   aqu 17.2288 2
NSVhi   Oct B   n/a 0   0
NSVhi   Oct B   terr    0   0
NSVhi   Oct C   aqu 22.7558 1
NSVhi   Oct C   n/a 0   0
NSVhi   Oct C   terr    24.7843 6
NSVhi   Aug D   aqu 0   0
NSVhi   Aug D   n/a 0   0
NSVhi   Aug D   terr    31.9222 7
NSVhi   Aug E   aqu 0.046   10
NSVhi   Aug E   n/a 0   0
NSVhi   Aug E   terr    0   0
NSVhi   Aug F   aqu 2.1156  5
NSVhi   Aug F   n/a 0   0
NSVhi   Aug F   terr    0   0

您还可以使用带有双循环的list comprehension：

SITE    DATE    INDIV   CATEGORY    BIOMASS LENGTH
GC  Oct C   aqu 0.1875  20
GC  Oct C   n/a 0   0
GC  Oct C   terr    0.5424  30
GC  Oct C   aqu 0.1875  20
GC  Oct C   n/a 0   0
GC  Oct C   terr    0.5424  30
GC  Oct A   aqu 0.0002  10
GC  Oct A   n/a 0   0
GC  Oct A   terr    0   0
GC  Aug D   aqu 7.4888  10
GC  Aug D   n/a 0   0
GC  Aug D   terr    100.9245    5
GC  Aug F   aqu 0   0
GC  Aug F   n/a 0   0
GC  Aug F   terr    20.593  10
GC  Aug D   aqu 7.4888  10
GC  Aug D   n/a 0   0
GC  Aug D   terr    100.9245    5
NSVhi   Oct B   aqu 17.2288 2
NSVhi   Oct B   n/a 0   0
NSVhi   Oct B   terr    0   0
NSVhi   Oct C   aqu 22.7558 1
NSVhi   Oct C   n/a 0   0
NSVhi   Oct C   terr    24.7843 6
NSVhi   Oct A   aqu 5.8713  5
NSVhi   Oct A   n/a 0   0
NSVhi   Oct A   terr    13.8651 3
NSVhi   Aug D   aqu 0   0
NSVhi   Aug D   n/a 0   0
NSVhi   Aug D   terr    31.9222 7
NSVhi   Aug D   aqu 0   0
NSVhi   Aug D   n/a 0   0
NSVhi   Aug D   terr    31.9222 7
NSVhi   Aug D   aqu 0   0
NSVhi   Aug D   n/a 0   0
NSVhi   Aug D   terr    31.9222 7

如果您想在from itertools import chain list1 = ['1','2','3'] list2 = ['a','b','c'] listNew = list(chain.from_iterable(zip(list1, list2))) # listNew = ['1', 'a', '2', 'b', '3', 'c']中连接元素对，那就是：

listNew = [y for x in zip(list1, list2) for y in x]
# listNew = ['1', 'a', '2', 'b', '3', 'c']

Answer 2

merged_list = []
length = min([len(list1), len(list2)])
for l in range(0,length):
   merged_list.append(list1[l])
   merged_list.append(list2[l])

print merged_list

Python中的合并列表

2 个答案: