我正在尝试使用数据库从中读取有效的登录信息。一列是用户名,另一列是密码。我如何编写我的代码,以便 IF 来自用户的用户名条目和用户的密码条目匹配数据库中的一行,它将验证登录并移动到下一页,这是示例名为" Screen"
我在下面制作了一个演示登录页面,其中添加了一个创建数据库功能。我必须编辑/添加什么来填补我的目标。
from tkinter import * #imports all the GUI libraries
from tkinter import messagebox #so it can be used outside idle
from tkinter import ttk
import sqlite3
class LoginPopup():
#constructor sets up the buttons
def __init__(Top):
Top.GenericGui = Tk()#creating a window
Top.GenericGui.title('Login')
Top.GenericGui.geometry('300x200+250+30')
Top.Check = 1
Top.GenericGui.iconbitmap('home.ico')
Password = StringVar()
Username = StringVar()
conn = sqlite3.connect('Logins.db')
c = conn.cursor()
#takes you back to the main menu
def BackToMain():
Top.delete()
openscreen = Screen()
def create_table():
c.execute("CREATE TABLE IF NOT EXISTS stuffToPlot(Username TEXT, Password TEXT)")
def read_from_db():
c.execute('SELECT * FROM stuffToPlot')
data = c.fetchone()
for row in data:
print(row)
def UsernameAndPassword(Top):
UsernameAttempt = Username.get()#how to get value from entry box
PasswordAttempt = Password.get()#how to get value from entry box
#Login Components
LoginVerify = ttk.Button(Top.GenericGui, text="Login", command = lambda: UsernameAndPassword(Top)).place(x=220,y=170)
ttk.Entry(Top.GenericGui,textvariable = Username,width = 20).place(x=140,y=60)
ttk.Entry(Top.GenericGui,show = '*',textvariable = Password,width = 20).place(x=140,y=100)#can hide letters entered with *
ttk.Label(Top.GenericGui,text = 'Username:').place(x=40,y=60)
ttk.Label(Top.GenericGui,text = 'Password:').place(x=40,y=100)
Label(Top.GenericGui,text = ' Please Enter Your Username \nand Password ',font = ('TkDefaultFont',12)).pack(side = TOP, fill = X)
create_table()
read_from_db()
c.close
conn.close()
class Screen(LoginPopup):
#constructor sets up the buttons
def __init__(Top):
Top.GenericGui = Tk()#creating a window
Top.GenericGui.title('Screen')
Top.GenericGui.geometry('300x200+250+30')
Top.Check = 1
Top.GenericGui.iconbitmap('home.ico')
Password = StringVar()
Username = StringVar()
runprogram = LoginPopup()
感谢您花时间阅读并感谢任何帮助