如何递归编写代码并在java中动态传递值，如下图所示？

Question

public static void getSome(int x) {
    int i, j, k, l, m, temp = (x - (x - 1));
    for (i = 1; i <= x; i++) {
        System.out.print("X");
    }
    System.out.println();
    for (l = 1; l >= (x / 2); l--) {
        for (j = 1; j <= l; j++) {
            System.out.print(" ");
        }
        System.out.print("X");
    }
    for (m = (x - (x + 1)); m >= 1; m--) {
        for (k = temp; k <= m; k--) {
            System.out.print(" ");
        }
        System.out.print("X");
        System.out.println();
    }
}

上面的代码有问题，即使它不是递归功能，你能不能请任何人帮帮我。

Answer 1

获得此输出

X     X
 X   X
  X X
   X
  X X
 X   X
X     X

使用此功能打印一行

private static void printRow(int width, int level) {
    StringBuilder sb = new StringBuilder();
    if (width < 1) return;

    for (int i = 0; i < level; i++) {
        sb.append(" ");
    }

    for (int i = 0; i < width; i++) {
        if (i == 0 || i == width - 1) {
            sb.append("X");
        }
        else {
            sb.append(" ");
        }
    }
    System.out.println(sb.toString());
}

这是硬编码的迭代方法

public static void main(String[] args) {
    printRow(7, 0);
    printRow(5, 1);
    printRow(3, 2);
    printRow(1, 3);
    printRow(3, 2);
    printRow(5, 1);
    printRow(7, 0);
}

这是递归方法

private static void printX(int width, int level) {
    if (width < 2) {
        if (width == 1) {
            printRow(width, level);
        }
        return;
    }
    printRow(width, level);
    printX(width - 2, level+1);
    printRow(width, level);
}

private static void printX(int width) {
    printX(width, 0);
}

public static void main(String[] args) {
    printX(7);
}