将表单字段插入数据库(Bottle,sqlite)

时间:2016-03-08 15:19:12

标签: python sqlite bottle

必须有一个更好的方法来做到这一点..我已经阅读了瓶子文档,但它并没有真正帮助那么多。这很有效,但很脏。好像我错过了什么。

@route('/client/new', method="POST")
def add_new_client():
    c = db.cursor()
    query = """INSERT INTO Clients VALUES(NULL, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)"""

    try:
        r = request.POST

        d = r['LastContact'].split('/') # mm/dd/yyyy
        try: lastcontact = datetime(int(d[2]), int(d[0]), int(d[1]))
        except Exception as e: lastcontact = datetime.now()

        try: taxExempt = r['TaxExempt'] 
        except Exception as e: taxExempt = 0

        c.execute(query, (r['FirstName'], r['LastName'], r['Address1'], r['Address2'], r['City'], r['State'], r['Zip'],
                 r['HomePhone'], r['CellPhone'], r['WorkPhone'], r['Email'], r['ContactMethod'], r['ContactTime'],
                 r['ContactFrequency'], lastcontact, taxExempt, r['TaxID'], r['Notes']))
        db.commit()
    except Exception as e:
        print "ERROR %s" % e
    redirect('/client/%d' % c.lastrowid)
    c.close()

1 个答案:

答案 0 :(得分:1)

如果您使用SQLAlchemy ORM相关文章:

,事情看起来会更加干净

如果您希望继续混合SQL和Python,可以使用命名/关键字查询占位符来简化代码,这样您就可以将r字典传递给查询:

d = r['LastContact'].split('/') # mm/dd/yyyy
try: 
    r['LastContact'] = datetime(int(d[2]), int(d[0]), int(d[1]))
except Exception as e: 
    r['LastContact'] = datetime.now()

if 'TaxExempt' not in r:
    r['TaxExempt'] = 0

query = """
    INSERT INTO 
        Clients 
    VALUES
        (NULL, 
         :FirstName, 
         :LastName, 
         :Address1, 
         :Address2, 
         :City, 
         :State, 
         :Zip, 
         :HomePhone, 
         :CellPhone, 
         :WorkPhone,
         :Email, 
         :ContactMethod, 
         :ContactFrequency, 
         :ContactTime, 
         :LastContact, 
         :TaxExempt, 
         :TaxID, 
         :Notes)
"""
c.execute(query, r)