我有以下方法:
public function getThreads()
{
$results = \DB::select(\DB::raw(config('sql.messages.threads')), [$this->user->user_id]);
$messagesThreadsModel = app()->make(MessagesThreadsModel::class);
$messages = [];
foreach ($results as $r) {
$message = $messagesThreadsModel->find($r->messages_thread_id);
$message->unread = $r->unread;
$messages[] = $message;
}
return $messages;
}
为了测试上面的内容,我模拟了调用\ DB :: select(通过Laravel'的外观)来返回对象列表,就像DB类通常那样。然后我加载消息线程模型,再次在容器中进行模拟和替换(因此app() - > make()将返回其模拟实例,而不是实际模型)。
最后:
$messagesThreadsModel->find($r->messages_thread_id);
再次模拟返回虚拟对象(存根?)。全部内容如下:
$threadsList = $this->mockThreads();
// mock the raw expression, check the query
\DB::shouldReceive('raw')->once()->with(m::on(function($sql)
{
return strpos($sql, 'messages') !== false;
}))->andReturn(true);
// mock the DB call, return a list of objects
\DB::shouldReceive('select')->once()->with(true, [$this->usersModel->user_id, $this->usersModel->user_id, $this->usersModel->user_id])->andReturn($threadsList);
$mockThreadResult = new \StdClass;
$mockThreadResult->last = "date";
$this->messagesThreadModel->makePartial();
// HERE IS THE TRICKY PART!
$this->messagesThreadModel->shouldReceive('find')->times(count($threadsList))->andReturn($mockThreadResult);
$this->app->instance('App\Freemiom\Models\Messages\MessagesThreads', $this->messagesThreadModel);
$messages = new Messages($this->usersModel);
$threadList = $messages->getThreads();
现在问题是什么?因为我传递了已创建的虚拟对象,所以每次在循环中调用 - > find方法时都会返回相同的对象。
我应该如何通过每次调用告诉mockery返回一个新对象?它甚至可能吗?或许我应该做一些代码重构以使其全部可测试?
答案 0 :(得分:2)
因此,为了能够在每次连续调用相同的模拟方法时返回一个新对象,我必须像这样使用 andReturnUsing :
$this->messagesThreadModel->shouldReceive('find')->times(count($threadsList))->andReturnUsing(function()
{
$mockThreadResult = new \StdClass;
$mockThreadResult->last = "date";
return $mockThreadResult;
});
这将模仿Eloquent模型的行为,该模型也使用find()方法返回新对象。