我有一个json文件mytest.json
,如下所示我想使用PowerShell script
更新值
update.json
{
"update": [
{
"Name": "test1",
"Version": "2.1"
},
{
"Name": "test2",
"Version": "2.1"
}
]
}
我想编写一个PowerShell脚本if Name=="test1" I want to update Version= "3"
我怎么能用参数做到?
答案 0 :(得分:58)
这是一种方式:
$a = Get-Content 'D:\temp\mytest.json' -raw | ConvertFrom-Json
$a.update | % {if($_.name -eq 'test1'){$_.version=3.0}}
$a | ConvertTo-Json -depth 32| set-content 'D:\temp\mytestBis.json'
根据@FLGMwt和@mikemaccana,我使用ConvertTo-Json
改进-depth 32
,因为默认深度值为2,对于深度大于2的对象,您将收到类信息,无论对象如何。
答案 1 :(得分:5)
我也遇到过同样的问题。我想更改以下 JSON 文件的记录
{
"SQS_QUEUE_URL": "https://que-url.com/server1",
"SQS_EVENTS_QUEUE_URL": "https://events-server.com/server1/development_events",
"REGION": "region1",
"BUCKET": "test-bucket",
"AE_WORK_PATH": "C:\\workpath\\path1",
"ENV": "env"
}
最后,我设法找到了从 Powershell 生成 JSON 文件的最简单方法。
$json = Get-Content "c:\users\bharat.gadade\desktop\test.json" | ConvertFrom-Json
$json.SQS_QUEUE_URL = "https://que-url.com/server2"
$json.SQS_EVENTS_QUEUE_URL = "https://events-server.com/Server2/development_events"
$json.REGION = "region1 "
$json.BUCKET = "test-bucket"
$json.AE_WORK_PATH = "C:\workpath\path1"
$json.ENV = "env"
$json | ConvertTo-Json | Out-File "c:\users\bharat.gadade\desktop\test.json"