我目前正在将VB6转换为C#。你能帮我转换一下这段代码吗?
这是VB6代码:
'This converts the bytes into test parameters
Sub getParamValues(ByRef TransData() As Byte, ByRef testparam() As Single, startbyte As Integer)
Dim tmpdata As bByteType
Dim convertedvalue As SingleType
Dim i As Integer
Dim bytecounter As Integer
bytecounter = startbyte
'On Error Resume Next
For i = 0 To 9
tmpdata.bBytes(0) = TransData(bytecounter + 3) 'TransData(0 + 3)
tmpdata.bBytes(1) = TransData(bytecounter + 2) 'TransData(0 + 2)
tmpdata.bBytes(2) = TransData(bytecounter + 1) 'TransData(0 + 1)
tmpdata.bBytes(3) = TransData(bytecounter) 'TransData (0)
'THIS CODE I WANT TO CONVERT
LSet convertedvalue = tmpdata
testparam(i) = convertedvalue.dResult 'Gets the test parameters
bytecounter = bytecounter + 4
Next i
End Sub
和这个
Private Type bByteType
bBytes(3) As Byte
End Type
Private Type SingleType
dResult As Single
End Type
我尽力将其转换为C#。但是我得到了NullException。我无法将Type
从Vb6转换为C#。所以,我试过struct
。但我不知道如何使用C#将bBytes
数据传输到tmpdata
。
public void getParamValues(ref byte[] TransData, ref Single[] testparam, int startbyte)
{
bByteType tmpdata = new bByteType();
SingleType convertedvalue = new SingleType();
//byte[] bBytes = new byte[4];
int bytecounter = 0;
bytecounter = startbyte;
for (int i = 0; i < 9; i++)
{
tmpdata.bBytes[0] = TransData[bytecounter + 3];
tmpdata.bBytes[1] = TransData[bytecounter + 2];
tmpdata.bBytes[2] = TransData[bytecounter + 1];
tmpdata.bBytes[3] = TransData[bytecounter];
//LSet convertedvalue = tmpdata <--- Supposed to convert to C#
testparam[i] = convertedvalue.dResult;
bytecounter = bytecounter + 4;
}
}
public struct bByteType
{
//byte[] bBytes = new byte[3];
public byte[] bBytes;
public bByteType(byte[] size)
{
bBytes = new byte[4];
}
}
struct SingleType
{
public Single dResult;
}
答案 0 :(得分:1)
VB6代码交换字节顺序以在big-endian和little-endian之间进行转换。即使结构定义完全不同,VB6中的LSet
也会将字节值从一个结构(Type
)复制到另一个结构。来自一个变量的二进制数据被复制到另一个变量的存储空间中,而不考虑为元素指定的数据类型。 Gulp!
在C#中执行此操作的最佳方法是something like this answer。
在C#中将字节值从一个结构复制到另一个结构要复杂得多 - 例如,您需要将结构固定在内存中以阻止它们在操作的中途移动。