Question

#include <iostream>

using namespace std;

void main(int argc, char* argv[])
{
    int conversion, hash;

    cout << "Select one." << endl;
    cout << "0: Radix Method 32" << endl;
    cout << "1: Radix Method 64" << endl;
    cout << "2: SumUp" << endl;
    cin >> conversion;

    cout << endl << "Select one." << endl;
    cout << "0: Division" << endl;
    cout << "1: Multiplication" << endl;
    cin >> hash;

    cout << "Conversion: " + conversion << endl;
    cout << "hash: " + hash << endl;
}

这很简单，我的输出很疯狂。我觉得这很明显，但我太累了，看不到它。我输入变量的数字是从下一个输出字符串中删除的字符数。例如：

Select one.
0: Radix Method 32
1: Radix Method 64
2: SumUp
1

Select one.
0: Division
1: Multiplication
2
onversion:
sh:
Press any key to continue . . .

Select one.
0: Radix Method 32
1: Radix Method 64
2: SumUp
5

Select one.
0: Division
1: Multiplication
1
rsion:
ash:
Press any key to continue . . .

我疯了还是没有意义？我使用cin错了吗？我几个月没有使用过C ++，但我看不出它有什么问题。

Answer 1

cout << "Conversion: " + conversion表示从数组头部后面的conversion元素打印。

您可能需要这样做（将+更改为<<）：

cout << "Conversion: " << conversion << endl;
cout << "hash: " << hash << endl;

cin正在吃输出流

1 个答案: