Question

喂谢谢您的回答。我尝试了2个代码，但它不起作用。我有一个JSON对象看起来像这样

[{"name":"aaa","0":"aaa","city":"paris","1":"paris","school":"gtdzh","2":"gtdzh"},
{"name":"bbb","0":"bbb","city":"berlin","1":"berlin","school":"gdezh","2":"gdezh"},
{"name":"ccc","0":"ccc","city":"new york","1":"new york","school":"asdzh","2":"asdzh"},
{"name":"aaa","0":"aaa","city":"sidney","1":"sidney","school":"gtdcv","2":"gtdcv"},
{"name":"bbb","0":"bbb","city":"paris","1":"paris","school":"gtdzh","2":"gtdzh"}]

我想填充一个下拉列表，其中包含从我的Json对象

字段中选择的不同值

例如：我有2个人在2个城市aaa和bbb学习。如何做到我的下拉列表中没有重复。

Answer 1

jQuery（＆amp; Javascript）没有太多用于处理数据数组。我建议您查看Underscore js library（用于补充jQuery），它可以处理各种数组操作。

Answer 2

你可以遍历对象;仅使用唯一字段创建一个新对象（这些行中的某些内容可行）：

function array_search (needle, haystack) {
    var key = '';
    for (key in haystack) {        
        if ((haystack[key] === needle) || (haystack[key] == needle)) {
            return key;
        }
    }
     return false;
}

（c / o http://phpjs.org/functions/array_search:335上面的函数）

var myNames = new Array();
var myFilteredObject = new Array();
for (i in myObject){
    if (array_search(myObject[i].name, myNames) == false){
        var myNames[i] = myObject[i].name;
        var myFilteredObject[] = myObject[i];
    }  
}

帮助从json对象中选择列表填充

2 个答案: