Question

所以这就是问题，我不确定我的数据库是否成功连接，如果是，那么我的输入查询不起作用。这就是我所拥有的。我确定我的错误是相当明显的，我可能会自己踢，但请帮忙。

HTML：

<form action="adduser.php" method="post">
    <label>Create Username</label><br>
    <input type="text" name="username" placeholder="Username" /><br>
    <label>Create Password</label><br>
    <input type="password" name="password" placeholder="Password" /><br>
    <label>Confirm Password</label><br>
    <input type="password" placeholder="Password" /><br>
    <label>Select Gender</label><br>
    <input type="radio" name="gender" value="Male">Male</button>
    <input type="radio" name="gender" value="Female">Female</button><br>
    <label>Click submit to continue</label><br>
    <button class="btn btn-primary" name="submit" type="submit">Submit</button>
   </form>

connect.php：

<?php
$username = "********";
$password = "***********";
$db = "localhost";
$dbconn = mysql_connect($db, $username, $password);
    if (!$dbconn){
        die ("Connection failure!");
    }

    return "Connection Successful.";

    mysql_select_db("who_do_it_db", $dbconn);
?>

adduser.php：

<?php

include 'connect.php';

$uName = $_POST['username'];
$pWord = $_POST['password'];
$gender = $_POST['gender'];

$query = 'INSERT INTO users(Username, Password, Gender) VALUES ("$uName","$pWord","$gender");';
$query = mysql_query($query);

Answer 1

您在附带的文件中有return。因此，脚本在那里完成，并且在include

中的adduser.php之后永远不会到达任何命令

问题将PHP文件中的内容添加到数据库

1 个答案: