Question

如何将高数字更改为：

1,000 = 1K
1,250 = 1,2K
10,200 = 10,2K
102,000 = 102K
1,200,000 = 1,2M

或类似的东西？

这是我设置数字的方式：

textCell?.ll1.text = "\(String(thumb[indexPath.row].count))"
textCell?.ll2.text = "\(String(love[indexPath.row].count))"

Answer 1

let formatter = NSByteCountFormatter()

就是这样;）

示例：

let oneFormattedNumber = formatter.stringFromByteCount(1025000000000)
let formattedList = [1_000, 1_250, 10_200, 102_000, 1_200_000].map(formatter.stringFromByteCount)

Answer 2

您可以将此功能添加为Int：
的扩展程序

extension Int {
  func shortLiteralDescription() -> String {
        var factor = 0
        let tokens = ["","K", "M", "G","T","P"] //If you think you will need to express more, add them here
        var value = Double(self);
        while (value > 1000) {
            value /= 1000
            factor++
        }
        return "\(value)\(tokens[factor])"
    }
}

然后：

400200.shortLiteralDescription()   //400.2K
4000.shortLiteralDescription()     //4.0K

将高数字转换为低格式

2 个答案: