Question

EG。档案1

git filter-branch --parent-filter \
 'test $GIT_COMMIT = 1234567890123456789012345678901234567890 && \
  echo "" || cat' -- --all

文件2

refs/original/

我想比较file1＆＃39;＆＃34; GATEWAY_GUID＆＃34;带有file2＆lt; device_gateway_guid列的列。输出应该是file1中看不到的file1的所有记录。

预期产出 "ACCOUNT_ID","CTN","NAME","GATEWAY_GUID","DEVICE_GUID","CATALOG_ID","FW_VERSION","DATE_CREATED","STATUS_ID","LOCATION_CODE","BAN","Market_Area","State","IMEI","HW_MODEL" "306875",="9404653975","14-052917 14-052917","313A0B72E3E440DD8687BD681E55FB03","0",="000010000010004","FW: 1.04.122, JVM: Oracle Corporation 1.7.0_72-ea, OS: Linux 2.6.33.5","06/24/2014 14:32:38","0",="0003013034",="177046772949","DLS","TX",="351612051721824","Cisco DLC-100" "306875",="9404653975","14-052917 14-052917","7EED6EE61F0949EE99554D4D4F09E4FE","ACFF000001",="000010901000004","1.2.14","06/24/2014 21:28:17","0",="",="177046772949","DLS","TX",="351612051721824","" "306875",="9404653975","14-052917 14-052917","D57DAE988A1C482EA3217312EDC7466E ","ACFF010904",="000010907000004","","12/16/2015 23:39:21","0",="",="177046772949","DLS","TX",="351612051721824","" [因为这可以在file1中看到，但不在file2中看到]

例如：如果文件1有10条记录而文件2有5000条记录。在5000个文件中，5个记录与文件1相同。然后我的输出文件应显示缺少file1中未见的5个列值。

Answer 1

2个文件之间的不同引用/间距会增加皱纹，但comm是此处使用的工具，具有正确准备的输入

comm -23 <(awk -F, 'NR > 1 && NF {gsub(/^"|"$/,"",$4);print $4}' file1 | sort) \
         <(awk -F, 'NR > 1 && NF {gsub(/^ | $/,"",$6);print $6}' file2 | sort)

D57DAE988A1C482EA3217312EDC7466E

-23选项会丢弃共同的行（-3）和file2（-2）唯一的行，这些字段对于file1是唯一的。

awk比较两个文件中的列并打印文件1列，如果在file2中没有看到[类似的帖子与此相关被错误地询问]

1 个答案: