Question

正如我写这段代码$this->setlist();这个错误，在写这行之前我没有遇到任何错误，你能帮我解决这个吗？

public function setlist(){
    $mysql = new Mysql();
    $query = "SELECT * FROM student where cohortid = '$this->cohort' && programid = '$this->program && departmentid = '$this->department'";
    $mysql->execute($query);
    while($row = $mysql->fetch_array()){
        $this->list[] = $row;
    }
    array_unshift($this->list, "test");
    unset($this->list[0]);
}


public function display_id_firstname_and_lastname(){
    *$this->setlist();*
    $html = new Html();
    $html->table("table table-bordered");

    $html->row();
    $html->column(); echo "S#"; $html->closecolumn();  $html->column(); echo "FirstName"; $html->closecolumn(); $html->column(); echo "LastName"; $html->closecolumn();
    $html->closerow();

    foreach($this->list as $key => $value){
        $html->row();
        $html->column(); echo $key; $html->closecolumn(); $html->column(); echo $value['firstname']; $html->closecolumn();
        $html->column(); echo $value['lastname']; $html->closecolumn();
        $html->closerow();

    }

    $html->closetable();
}

Answer 1

首先，您错过了一个变量周围的'。

其次，您应该使用AND而不是&&

第三，如果你想从一个对象属性中获取值，当在双引号字符串文字中使用时，将{}中的字段包装起来。

$query = "SELECT * 
    FROM student 
    WHERE cohortid = '{$this->cohort}' 
      AND programid = '{$this->program}' 
      AND departmentid = '{$this->department}'";

您的SQL语法有错误;检查与MySQL服务器版本对应的手册，以便在第1行的“1”附近使用正确的语法

1 个答案: