A使用UTF-8解码的字符串%c3%ad
为í
,但使用ASCII解码为Ã
。
我需要使用UTF-8编码对其进行解码,我该怎么做?
这是一个值的选择以及应该是什么......
SELECT
('%c3%81') as 'Á (81 = 129)',
('%c3%89') as 'É (89 = 137)',
('%c3%8d') as 'Í (8d = 141)',
('%c3%93') as 'Ó (93 = 147)',
('%c3%9a') as 'Ú (9a = 154)'
SELECT
('%c3%a1') as 'á (a1 = 161)',
('%c3%a9') as 'é (a9 = 169)',
('%c3%ad') as 'í (ad = 173)',
('%c3%b3') as 'ó (b3 = 179)',
('%c3%ba') as 'ú (ba = 186)'
答案 0 :(得分:1)
这个功能似乎可以胜任。
CREATE FUNCTION [dbo].[UrlDecodeUTF8](@URL varchar(3072))
RETURNS varchar(3072)
AS
BEGIN
DECLARE @Position INT,
@Base CHAR(16),
@Code INT,
@Pattern CHAR(21)
SELECT @URL = REPLACE(@URL, '%c3', '')
SELECT @Base = '0123456789abcdef',
@Pattern = '%[%][0-9a-f][0-9a-f]%',
@Position = PATINDEX(@Pattern, @URL)
WHILE @Position > 0
SELECT @Code = Cast(CONVERT(varbinary(4), '0x' + SUBSTRING(@URL, @Position + 1, 2), 1) As int),
@URL = STUFF(@URL, @Position, 3, NCHAR(@Code + 64)),
@Position = PATINDEX(@Pattern, @URL)
RETURN REPLACE(@URL, '+', ' ')
END