SQL Consolidate Column

Question

我想获取在列下找到的所有字符串，并根据它们构建字符串组合。

举例说明：

对象（o）

id  group_id   name        type                     
----------------------------------------------------
1   100        Computer    Computer - Standard
2   100        Telephone   Telephone - Modified
3   100        Table       Table - Standard - Deal

正如您在type下看到的那样，我正在寻找单词Standard和Modified（还有其他人，但为了简单起见我只显示了2）并希望构建一个字符串组合这些单词一次，并将结果作为每行的列。

我可以使用CASE和LIKE获取每行的关键字，并将该字词指定为列的值，如下所示：

id  group_id   name        type                     consolidated
-----------------------------------------------------------------------
1   100        Computer    Computer - Standard      Standard
2   100        Telephone   Telephone - Modified     Modified
3   100        Table       Table - Standard - Deal  Standard

但那不是我想要的。我只是不知道如何像我想的那样加入他们。

id  group_id   name        type                     consolidated
-----------------------------------------------------------------------
1   100        Computer    Computer - Standard      Standard / Modified
2   100        Telephone   Telephone - Modified     Standard / Modified
3   100        Table       Table - Standard - Deal  Standard / Modified

修改

抱歉，我忘了添加当前的查询。

SELECT o.id, o.group_id, o.name, o.type,
CASE
  WHEN o.type LIKE '%Standard%' THEN 'Standard'
  WHEN o.type LIKE '%Modified%' THEN 'Modified'
  ELSE ''
END AS consolidated
FROM objects o
WHERE o.group_id = 100

Answer 1

WITH q as (
    SELECT o.id, o.group_id, o.name, o.type,
    CASE
        WHEN o.type LIKE '%Standard%' THEN 'Standard'
        WHEN o.type LIKE '%Modified%' THEN 'Modified'
        ELSE ''
    END AS lbl
    FROM objects o
    WHERE o.group_id = 100
)
SELECT
    id, group_id, name, type,
    (
      SELECT LISTAGG(lbl, ' / ') WITHIN GROUP (ORDER BY ??)
      FROM (SELECT DISTINCT lbl FROM q) dc
    ) as consolidated
FROM q;