Question

所以我试图获取我创建的SQL数据库的所有信息并在列表视图中显示它但是我遇到错误＆＃34;无法解析符号TABLE_NAME＆＃34;即使它被定义为页面顶部的公共静态字符串。

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Answer 1

TABLE_NAME不是COL_1的属性。也许你的意思是

Cursor cursor = db.query(TABLE_NAME, projections, null, null, null, null, null);

Answer 2

您正尝试访问COL_1.TABLE_NAME作为db.query（）的参数。我建议删除COL_1.。

Answer 3

你需要创建一个表。

就像这样;

public class database_helper extends SQLiteOpenHelper {
    public static final String DATABASE_NAME = "test.db";

    public static final String TABLE_NAME = "testtable";

    public static final String COL_1 = "ID";
    public static final String COL_2 = "NAME";
    public static final String COL_3 = "LASTNAME";
}

公共游标无法解析符号

3 个答案: