Question

我有这个

var regex = new Regex(@"StartDate:(.*)EndDate:(.*)W.*Status:(.*)");

所以这会让我获得值，直到它击中字符串中的W是正确的？ - 我需要它停在W OR S.我尝试了几种不同的方法，但我没有让它工作。有人得到了一些信息吗？

更多信息：

            record = record.Replace(" ", "").Replace("\r\n", "").Replace("-", "/");
            var regex = new Regex(@"StartDate:(.*)EndDate:(.*)W.*Status:(.*)");
            string strStartDate = regex.Match(record).Groups[1].ToString();
            string strEndDate = regex.Match(record).Groups[2].ToString();
            string Status = regex.Match(record).Groups[3].ToString().ToUpper().StartsWith("In") ? "Inactive" : "Active";

我正在尝试解析一大串值，我只想要3件事 - 开始日期，结束日期和状态（活动/非活动）。但是，每个值有3个不同的值（3个开始日期，3个结束日期，3个状态＆＃39;）

前2个字符串就像这样

"Start Date: 

 2014-09-08 



End Date: 

 2017-09-07 



Warranty Type: 

 XXX 



Status: 

 Active 



Serial Number/IMEI: 

 XXXXXXXXXXX









Description:



XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX"

第三个字符串就像这样

"Start Date: 

 2014-09-08 



End Date: 

 2017-09-07 



Status: 

 Active 



Warranty Upgrade Code:



SVC_PRIORITY"

在最后一个字符串上，由于猜测结束日期后W.*，它不会显示日期

我没有在最后一个字符串中获得2个日期

Answer 1

无需替换示例中的新行

List<string> resultList = new List<string>();

var subjectString = @"Start Date: xxxxx
End Date: yyyy
Warranty Type: zzzz
Status: uuuu
Start Date: aaaa
End Date: bbbb
Status: cccc";

Regex regexObj = new Regex(@"Start Date: (.*?)\nEnd Date: (.*?)\n(.|\n)*?Status: (.*)");
Match matchResult = regexObj.Match(subjectString);
while (matchResult.Success) {
    resultList.Add(matchResult.Groups[1].Value);
    resultList.Add(matchResult.Groups[2].Value);
    resultList.Add(matchResult.Groups[4].Value);
    matchResult = matchResult.NextMatch();
}

Answer 2

编辑请尝试使用正则表达式解析函数：

using System.Text.RegularExpressions;
using System.Linq;
using System.Windows.Forms;

private static List<string[]> parseString(string input)
{
    var pattern = @"Start\s+Date:\s+([0-9-]+)\s+End\s+Date:\s+([0-9-]+)\s+(?:Warranty\s+Type:\s+\w+\s+)?Status:\s+(\w+)\s*";
    return Regex.Matches(input, pattern).Cast<Match>().ToList().ConvertAll(m => new string[] { m.Groups[1].Value, m.Groups[2].Value, m.Groups[3].Value });

}

// To show the result string
var result1 = parseString(str1);
string result_string = string.Join("\n", result1.ConvertAll(r => string.Format("Start Date: {0}\nEnd Date: {1}\nStatus: {2}", r)).ToArray());
MessageBox.Show(result_string);

输出：

EDIT2 对于OP的情况，您可以从foreach循环内部调用该函数，如下所示：

foreach (HtmlElement el in webBrowser1.Document.GetElementsByTagName("div"))
{
    if (el.GetAttribute("className") == "fluid-row Borderfluid")
    {
        string record = el.InnerText;
        //if record is the string to parse
        var result = parseString(record);
        var result_string = string.Join("\n", result.ConvertAll(r => string.Format("Start Date: {0}\nEnd Date: {1}\nStatus: {2}", r)).ToArray());
        MessageBox.Show(result_string);
    }
}

Answer 3

您可以使用以下代码替换代码（see IDEONE demo）：

var s = @"Start Date: xxxxx
End Date: xxxx
Warranty Type: xxxx
Status: xxxx";
var res = Regex.Replace(s, @":\s+", ": ")            // Remove excessive whitespace
        .Split(new[] { "\r", "\n" }, StringSplitOptions.RemoveEmptyEntries) // Split each line with `:`+space
        .ToDictionary(n => n[0], n => n[1]);              // Create a dictionary
string strStartDate = string.Empty;
string strEndDate = string.Empty;
string Status = string.Empty;
string Warranty = string.Empty;
// Demo & variable assignment
if (res.ContainsKey("Start Date")) {
    Console.WriteLine(res["Start Date"]);
    strStartDate = res["Start Date"];
}
if (res.ContainsKey("Warranty Type")) {
    Console.WriteLine(res["Warranty Type"]);
    Warranty = res["Warranty Type"];
}
if (res.ContainsKey("End Date")) {
    Console.WriteLine(res["End Date"]);
    strEndDate = res["End Date"];
}
if (res.ContainsKey("Status")) {
    Console.WriteLine(res["Status"]);
    string Status = res["Status"];
}

请注意，最好的方法是使用WarrantyType，StartDate等字段声明自己的类，并在LINQ代码中对其进行初始化。

Answer 4

避免.*抓住所有导致正则表达式模式创建者陷入困境的问题。而是创建模式以匹配数据中始终发生的数据中的特定模式。

您的模式是\d\d\d\d-\d\d-\d\d\d\d的两个日期，其余的是锚文本，应该用作可以跳过的静态锚点。

以下是查找日期模式的示例。一旦找到，正则表达式将其置于命名匹配捕获组(?<GroupNameHere>...)中，Linq将每个匹配提取到动态实体中并解析日期时间。

数据

请注意，根据您的示例
，第一个日期会相反
var data = @"Start Date: 2014-09-08 End Date: 2017-09-07 Status: Active Start Date: 2014-09-09 End Date: 2017-09-10 Status: In-Active ";

<强>模式

string pattern = @" ^Start\sDate:\s+ # An anchor of start date that always starts at the BOL (?<Start>\d\d\d\d-\d\d-\d\d) # actual start date pattern \s+ # a lot of space including \r\n ^End\sDate:\s+ # End date anchor and space (?<End>\d\d\d\d-\d\d-\d\d) # pattern of the end date. \s+ # Same pattern as above for Status ^Status:\s+ (?<Status>[^\s]+) ";

<强>处理

// Explicit hints to the parser to ingore any non specified matches ones outside the parenthesis(..) // Multiline states ^ and $ are beginning and eol lines and not beginning and end of buffer. // Ignore allows us to comment the pattern only; does not affect processing. Regex.Matches(data, pattern, RegexOptions.ExplicitCapture | RegexOptions.Multiline | RegexOptions.IgnorePatternWhitespace) .OfType<Match>() .Select (mt => new { Status = mt.Groups["Status"].Value, StartDate = DateTime.Parse(mt.Groups["Start"].Value), EndDate = DateTime.Parse(mt.Groups["End"].Value) })

<强>结果

C＃Regex语法帮助解析字符串

4 个答案: