Question

尝试使用spring integration ws使用web服务，在webservice端，我得到一个空指针，因为看起来传递的对象没有被编组或没有映射到xml中，下面是客户端调用服务的片段。

public class Main {

public static void main(String[] args) {
    ClassPathXmlApplicationContext context
            = new ClassPathXmlApplicationContext("springws.xml");
    MessageChannel channel = context.getBean("request", MessageChannel.class);

      String body = "<getPojo xmlns=\"http://johnson4u.com/\"><pojo>\n"
            + "    <pojoId>23</pojoId>\n"
            + "    <pojoName>dubic</pojoName>\n"
            + "</pojo></getPojo>";

    MessagingTemplate messagingTemplate = new MessagingTemplate();
    Message<?> message = messagingTemplate.sendAndReceive(
            channel, MessageBuilder.withPayload(body).build());

    System.out.println(message.getPayload());
}

WSDL由JAxWS端点类

生成

  package com.johnson4u;


  import javax.jws.WebService;
  import javax.jws.WebMethod;
  import javax.jws.WebParam;


@WebService(serviceName = "SpringService")
public class SpringService {


@WebMethod(operationName = "getPojo" )
public Pojo getPojo(@WebParam(Pojo pjRequest){
    //Null Pointer occurs here as pjRequest might not be mapped to xml

   System.out.println("Pojo name is "+pjRequest.getPojoName());

   return new Pojo(234,"IM new Pojo");
}

和POJO

  package com.johnson4u;


public class Pojo {

private int pojoId;
private String pojoName;

public Pojo(int pojoId, String pojoName) {
    this.pojoId = pojoId;
    this.pojoName = pojoName;
}


public int getPojoId() {
    return pojoId;
}

public void setPojoId(int pojoId) {
    this.pojoId = pojoId;
}

public String getPojoName() {
    return pojoName;
}

public void setPojoName(String pojoName) {
    this.pojoName = pojoName;
}

不幸的是，stackoverflow无法正确格式化wsdl，但是命名空间ID基于包名com.johnson4u，下面是spring-ws-context.xml

<int:channel   id="request" />      
<int:channel id="response" />

<ws:outbound-gateway  id="gateway"   
                      request-channel="request"   
                      uri="http://localhost:20151/SpringWs/SpringService?wsdl"/>

Answer 1

我相信弦体应该是

String body = "<ns:getPojo xmlns:ns=\"http://johnson4u.com/\"><pojo>\n"
            + "    <pojoId>23</pojoId>\n"
            + "    <pojoName>dubic</pojoName>\n"
            + "</pojo><ns:/getPojo>";

未包含命名空间符号“ns”

Answer 2

我相信要对象进行非编组，你需要在对象类中指定元素。

public class Pojo {
    @XmlElement(name="pojoId", required=true, namespace=YOUR_NAME_SPACE)
    private int pojoId;
    @XmlElement(name="pojoName", required=true, namespace=YOUR_NAME_SPACE)
    private String pojoName;

    // Getters and Setters ......
}

Answer 3

我将网络参数值更改为

  @WebMethod(operationName = "getPojo" )
   public Pojo getPojo(@WebParam(name = "pojo") Pojo pjRequest){

  System.out.println("Pojo name is "+pjRequest.getPojoName());

   return new Pojo(234,"IM new Pojo");
 }
    }

和xml请求

       String body = "<ns0:getPojo    xmlns:ns0=\"http://johnson4u.com/\">\n" +
 "               <pojo>"
             + "<pojoId>456</pojoId>"
              +"<pojoName>Johnson</pojoName>"
                + "</pojo>\n" +
       "        </ns0:getPojo>";

当soap消息调用Web服务时，NullPointer

3 个答案: