Question

我有一个mysql查询GROUP BY，HAVING。

查询工作正常现在需要删除相同的记录，当我尝试删除这些记录时，我收到错误。

选择查询

SELECT * FROM user_location_history WHERE (TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE())>30) AND user_id IN (SELECT user_id FROM user_location_history WHERE (TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE()) < 30) GROUP BY user_id HAVING COUNT(1) > 100) ORDER BY id ASC LIMIT 200

删除查询

DELETE FROM user_location_history WHERE (TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE())>30) AND user_id IN (SELECT user_id FROM user_location_history WHERE (TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE()) < 30) GROUP BY user_id HAVING COUNT(1) > 100) ORDER BY id ASC LIMIT 200

错误

错误代码：1093 您无法在FROM子句

中为更新指定目标表'user_location_history'

Answer 1

解决此问题的一种方法是将子查询包装在另一个子查询中：

DELETE FROM user_location_history 
WHERE TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE())>30
       AND 
       user_id IN (
          SELECT user_id 
          FROM (SELECT user_id 
                FROM user_location_history 
                WHERE TIMESTAMPDIFF(DAY,
                                    FROM_UNIXTIME(location_date/1000),
                                    SYSDATE()) < 30
                GROUP BY user_id 
                HAVING COUNT(1) > 100) AS t)
ORDER BY id ASC LIMIT 200

Answer 2

将您的选择查询作为嵌套子查询，然后以下将为您工作

DELETE FROM user_location_history
WHERE TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE())>30
      AND 
      user_id IN 
          (
            select * from 
            (
             SELECT user_id 
             FROM user_location_history
             WHERE TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE()) < 30
             GROUP BY user_id HAVING COUNT(1) > 100
            )t
          ) 
ORDER BY id ASC LIMIT 200

使用GROUP BY，HAVING写删除查询

2 个答案: