Question

所以，我的代码只有4行。我正在尝试连接到一个网站，之后我想要做的是无关紧要的，因为错误是在没有其他代码的情况下产生的。

import urllib.request
from bs4 import BeautifulSoup 

html=urllib.request.urlopen('http://python-data.dr-chuck.net/known_by_Fikret.html').read()
soup=BeautifulSoup(html,'html.parser')

和错误（简明扼要地总结一下）：

for res in _socket.getaddrinfo(host, port, family, type, proto, flags):
socket.gaierror: [Errno 11002] getaddrinfo failed
During handling of the above exception, another exception occurred:
urllib.error.URLError: <urlopen error [Errno 11002] getaddrinfo failed>

这是我尝试过的。

我在google上搜索了错误返回“urlopen错误[Errno 11002]”，特别是在stackoverflow上，没有回复任何帮助（实际上对于此错误没有太多问题被问到11002。）
所以然后我尝试用另一个网站“http://python-data.dr-chuck.net/known_by_Fikret.html”替换urlopen函数中的网站参数（即“http://www.pythonlearn.com/code/urllinks.py”）。它运作得很好。没有错误出现。
所以我猜这个错误必须与这个特定的网站本身有关。该网站有点动态，我的意思是它的内容会改变并变成另一个完全不同的东西。但我没有更多的知识，只是为了描述我看到的东西。

以及更长和完整版本的错误：

Traceback (most recent call last):
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 1240, in do_open
h.request(req.get_method(), req.selector, req.data, headers)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 1083, in request
self._send_request(method, url, body, headers)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 1128, in _send_request
self.endheaders(body)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 1079, in endheaders
self._send_output(message_body)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 911, in _send_output
self.send(msg)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 854, in send
self.connect()
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\http\client.py", line 826, in connect
(self.host,self.port), self.timeout, self.source_address)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\socket.py", line 693, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\socket.py", line 732, in getaddrinfo
for res in _socket.getaddrinfo(host, port, family, type, proto, flags):
socket.gaierror: [Errno 11002] getaddrinfo failed

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
File "D:/baiduyundownload/Tempo/Active/Python/Python Examples/Fileanalysis11111.py", line 4, in <module>
html=urllib.request.urlopen('http://python-data.dr-chuck.net/known_by_Fikret.html').read()
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 162, in urlopen
return opener.open(url, data, timeout)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 465, in open
response = self._open(req, data)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 483, in _open
'_open', req)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 443, in _call_chain
result = func(*args)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 1268, in http_open
return self.do_open(http.client.HTTPConnection, req)
File "C:\Users\Administrator\AppData\Local\Programs\Python\Python35-32\lib\urllib\request.py", line 1242, in do_open
raise URLError(err)
urllib.error.URLError: <urlopen error [Errno 11002] getaddrinfo failed>

Answer 1

这意味着您的DNS系统无法正常运行，或者您必须在网络上使用代理并且未正确定义。

如果您需要使用代理，请将环境变量HTTP_PROXY（以及可选的HTTPS_PROXY）设置为网络的正确配置。格式为http://proxy.example.com:80;如果您的代理需要用户名和密码，则应将其传入，如下所示：http://username:password@proxy.example.com:80。

对于DNS问题，请尝试从命令行查找域。打开命令提示符并键入nslookup python-data.dr-chuck.net，看看它是否返回给您IP地址。

Answer 2

这是DNS的问题;显然你的python程序无法解析你提供的URL的主机名。也许DNS正在运行的主机上配置错误？

此外，我可以建议使用请求库吗？这是一个更好，更易于使用的模块来执行Web请求。你会在这里找到它：https://pypi.python.org/pypi/requests

urllib.error.URLError：<urlopen error =“”[errno =“”11002] =“”getaddrinfo =“”failed =“”>？

2 个答案: