Question

我是mysql和php的新手，我试图只使用一个表单将值插入两个不同的表中

它一直在说 mysqli_num_rows（）期望参数1为mysqli_result mysqli_fetch_array（）期望参数1为mysqli

<?php

include('dbconn.php'); // Database connection and settings
if (isset($_POST['Submit'])) {

    $username    = $_POST["username"];
    $password    = $_POST["password"];
    $firstname   = $_POST["firstname"];
    $middlename  = $_POST["middlename"];
    $lastname    = $_POST["lastname"];
    $email       = $_POST["email"];
    $mobile      = $_POST["mobile"];
    $telephone   = $_POST["telephone"];

    $username    = trim(mysqli_escape_string($con, $username));
    $password    = trim(mysqli_escape_string($con, $password));
    $firstname   = trim(mysqli_escape_string($con, $firstname));
    $middlename  = trim(mysqli_escape_string($con ,$middlename));
    $lastname    = trim(mysqli_escape_string($con, $lastname));
    $email       = trim(mysqli_escape_string($con, $email));
    $mobile      = trim(mysqli_escape_string($con, $mobile));
    $telephone   = trim(mysqli_escape_string($con, $telephone));


    $sql    = "SELECT accholder_Username FROM tbl_accholder WHERE accholder_Username='$username'";
    $sql2   = "SELECT contacts_email FROM tbl_contacts WHERE contacts_email='$email'";
    $result = mysqli_query($con, $sql);
    $result2= mysqli_query($con, $sql2);
    $row    = mysqli_fetch_array($result, MYSQLI_ASSOC);
    $row2   = mysqli_fetch_array($result2,MYSQLI_ASSOC);

    if (mysqli_num_rows($result && ) == 1) {
        echo "Sorry...This Username already exist..";
    } 
    else if (mysqli_num_rows($result2) == 1) {
        echo "Sorry...This Email already exist..";
    } 
    else {
        $query = mysqli_query($con, "INSERT INTO tbl_accholder( accholder_Fname, accholder_Mname, accholder_Lname, accholder_Username, accholder_Password) 
VALUES ('$firstname', '$middlename', '$lastname','$username','$password')");
        $query2 = mysqli_query($con, "INSERT INTO tbl_contacts( contacts_email, contacts_mobile, contacts_telephone, acchold_ID) 
VALUES ('$email', '$mobile', '$telephone')");
        if ($query && $query2) {
            echo "Thank You! you are now registered.";
        }
    }
}

?>

Answer 1

您的$ sql变量包含无效的SQL语句，因为您尝试连接两个单独的SELECT查询。

不插入tbl_contacts

1 个答案: