Question

我在选择器中遇到state_selected问题。

<item
    android:state_selected="true"

    android:drawable="@drawable/red"
    ></item>

<item
    android:state_pressed="true"

    android:drawable="@drawable/blue"
    ></item>

<item
    android:drawable="@drawable/white"></item>

布局：

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical" android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:clickable="true">

    <TextView
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:id="@+id/list_item"
        android:textAppearance="?android:textAppearanceLarge"
        android:gravity="center"
        android:text = "Hello"
        android:background="@drawable/my_selector"
    />

</LinearLayout>

state_pressed工作正常（setEnabled方法有一个“true”值）。有什么建议吗？

Answer 1

要从选择器（while ( i <= 100) { number = i + 1 + "<br />"; i = i + 1; // Increment counter outputAreaRef.innerHTML = outputAreaRef.innerHTML + number; }）获得@drawable/red背景，您应该选择android:state_selected="true"：

TextView

为了更好地了解每个观点的状态，请检查
https://developer.android.com/reference/android/graphics/drawable/StateListDrawable.html#attr_android:state_selected

Android state_selected不起作用

1 个答案: