Question

我想从给定的mp3文件中提取字节数组，以便对后者应用快速傅立叶变换。执行的FFT将为我的宠物项目音乐推荐系统提供一些功能。

我编写了以下代码来从给定的mp3文件中提取字节：

public class TrackSample {

private static byte[] readBytesInPredefinedFormat(TargetDataLine format, InputStream inStream) throws IOException {
    ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
    byte[] buffer = new byte[8192];
    int bytesRead;
    while ((bytesRead = inStream.read(buffer)) > 0) {
        int count = format.read(buffer, 0, buffer.length);
        if (count > 0) {
            byteArrayOutputStream.write(buffer, 0, count);
        }
        byteArrayOutputStream.write(buffer, 0, bytesRead);
    }
    byte[] bytes = byteArrayOutputStream.toByteArray();
    byteArrayOutputStream.close();
    inStream.close();
    return bytes;
}

public static byte[] getTrackBytes(String pathToTrackSample) throws IOException, LineUnavailableException {
    FileInputStream fileInputStream = new FileInputStream(pathToTrackSample);
    final AudioFormat format = CurrentAudioFormat.getAudioFormat(); //Fill AudioFormat with the wanted settings
    DataLine.Info info = new DataLine.Info(TargetDataLine.class, format);

    TargetDataLine line = (TargetDataLine) AudioSystem.getLine(info);
    line.open(format);
    line.start();

    return readBytesInPredefinedFormat(line, fileInputStream);
    }
}

指定的音频格式为

public class CurrentAudioFormat {

    public static AudioFormat getAudioFormat(){
        float sampleRate = 44100;
        int sampleSizeInBits = 8;
        int channels = 1; //mono
        boolean signed = true;
        boolean bigEndian = true;
        return new AudioFormat(sampleRate, sampleSizeInBits, channels, signed, bigEndian);
    }
}

我尝试在以下mp3文件中测试此代码：

File type ID:   MPG3
Num Tracks:     1
----
Data format:     2 ch,  44100 Hz, '.mp3' (0x00000000) 0 bits/channel, 0 bytes/packet, 1152 frames/packet, 0 bytes/frame
                no channel layout.
estimated duration: 104.176325 sec
audio bytes: 4167053
audio packets: 3988
bit rate: 320000 bits per second
packet size upper bound: 1052
maximum packet size: 1045
audio data file offset: 3169
optimized
audio 4591692 valid frames + 576 priming + 1908 remainder = 4594176

系统特征是：

处理器：Intel核心i5,1.4 GHz;
RAM：DDR3,4Gb
操作系统：Mac OS X El Captain

从这个mp3文件中提取字节数组大约需要5分钟。

可能出现的瓶颈是什么？如何改进它们？

Answer 1

读取您需要的字节

while ((bytesRead = inStream.read(buffer)) > -1) {
    byteArrayOutputStream.write(buffer, 0, bytesRead);
}

我不知道你为什么要读两次。

要确保您所获得的是正确的，请尝试将其重新保存为新的音频文件。

-

读取音频文件的标准方法是

AudioInputStream audioInputStream=null;
  try {
    audioInputStream=AudioSystem.getAudioInputStream(new File(file));
  }
  catch(UnsupportedAudioFileException auf) { auf.printStackTrace(); }

然后将此audioInputStream传递给您的阅读方法。

将mp3文件输入流转换为字节输出流的性能问题

1 个答案: