Question

我需要转换这个......

# 4.0.0 - 2016-01-01
- some text without category

# 3.12.0 - 2016-02-01
- Category: some text

# 3.11.4 - 2016-03-01
- Category: some multiple text
- Something: some text
- Anything: more text

...进入（对象）数组。我不知道如何保持所有元素与其版本相关联。

结果应如下所示（最后一个块的示例）

[
    { 
        major: 3,
        minor: 11,
        patch = 4,
        date = '2016-03-01',
        entries = [
            { category: 'Category', 'some multiple text' },
            { category: 'Something', 'some text' },
            { category: 'Anything', 'more text' }
        ]
    }
]

正如您在第一个区块中所看到的，在entries中，字段category是可选的。

这就是我尝试的方法：

var lines = text.split('\n');
for(var i = 0;i < lines.length;i++){
    var meta = lines[i].split(' ');
    var version = meta[1].split('.');
    result['major'] = version[0];
    result['minor'] = version[1];
    result['patch'] = version[2];
    result['date'] = meta[3]
}

但这仅适用于每个区块的第一行。

Answer 1

此提案将字符串拆分为块并测试#或-的块。评估这些行并将其添加到结果中。

var text = '# 4.0.0 - 2016-01-01\n- some text without category\n- Just a text: with double point\n\n# 3.12.0 - 2016-02-01\n- Category: some text\n\n# 3.11.4 - 2016-03-01\n- Category: some multiple text\n- Something: some text\n- Anything: more text',
    result = function (text) {
        var array = text.split('\n'),
            o, r = [];
        array.forEach(function (a) {
            var p, v;
            if (a[0] === '#') {
                o = {};
                p = a.match(/^# ((.*) - )?(.*)$/);
                v = p[2].split('.');
                o.major = v[0];
                o.minor = v[1];
                o.patch = v[2];
                o.date = p[3];
                r.push(o);
            }
            if (a[0] === '-') {
                if (!o.entries) {
                    o.entries = [];
                }
                p = a.match(/^- ((\w*): )?(.*)$/);
                o.entries.push({ category: p[2], value: p[3] });
            }
        });
        return r;
    }(text);

document.write('<pre>' + JSON.stringify(result, 0, 4) + '</pre>');

Answer 2

这可以通过为不同类型的行和一些正则表达式编写不同的函数来解决：

var text = `# 4.0.0 - 2016-01-01
- some text without category

# 3.12.0 - 2016-02-01
- Category: some text

# 3.11.4 - 2016-03-01
- Category: some multiple text
- Something: some text
- Anything: more text`;

var lines = text.split('\n');
var all = [];
for(var i = 0;i < lines.length;i++){
  var firstChar = lines[i].substr(0, 1);
  if (firstChar === '#'){
    all.push(extractVersionInfo(lines[i]));
  }
  else if (firstChar === "-"){
    all[all.length-1].entries.push(extractNote(lines[i]));
  }
}
console.log(all);

function extractNote(text){
  var withoutDash = text.substr(2);
  if (withoutDash.indexOf(":") !== -1){
    var parts = withoutDash.split(":");
    return {category: parts[0],
        value: parts[1]
       };
  }
  else {
    return {value: withoutDash};
  }
}

function extractVersionInfo(text){
  var pattern = /# ([0-9]+)\.([0-9]+)\.([0-9]+) - ([0-9]{4}-[0-9]{2}-[0-9]{2})/;
  var match = text.match(pattern);
  result = {};
  result.major = match[1];
  result.minor = match[2];
  result.patch = match[3];
  result.date = match[4];
  result.entries = [];
  return result;
}

输出：

[ { major: '4',
    minor: '0',
    patch: '0',
    date: '2016-01-01',
    entries: [ { value: 'some text without category' } ] },
  { major: '3',
    minor: '12',
    patch: '0',
    date: '2016-02-01',
    entries: [ { category: 'Category', value: ' some text' } ] },
  { major: '3',
    minor: '11',
    patch: '4',
    date: '2016-03-01',
    entries: 
     [ { category: 'Category', value: ' some multiple text' },
       { category: 'Something', value: ' some text' },
       { category: 'Anything', value: ' more text' } ] } ]

JS：将文本转换为对象数组

2 个答案: