Question

我正在使用SQL Server Management Studio 2014，我正在编写一个存储过程以插入带有外键的许多表中。

我遇到两个错误：

Msg 547，Level 16，State 0，Procedure insertintoorders，Line 163
  INSERT语句与FOREIGN KEY约束冲突＆＃34; FK__Customers__Addre__145C0A3F＆＃34;。冲突发生在数据库＆＃34; FlowerCompany＆＃34;，table＆＃34; dbo.Addresses＆＃34;，column＆＃39; AddressID＆＃39;。

Msg 547，Level 16，State 0，Procedure insertintoorders，Line 178
  INSERT语句与FOREIGN KEY约束冲突＆＃34; FK__Orders__Customer__1FCDBCEB＆＃34;。冲突发生在数据库＆＃34; FlowerCompany＆＃34;，table＆＃34; dbo.Customers＆＃34;，column＆＃39; CustomerID＆＃39;。

这是我的存储过程和我的测试执行：

CREATE PROCEDURE insertintoorders
    @Street varchar(50), 
    @City varchar(30), 
    @State varchar(2), 
    @Zip varchar(9),
    @Phone varchar(10),
    @FlowerName varchar(50), 
    @FirstName varchar(40),
    @LastName varchar(40),
    @OrderStatus varchar(12),
    @DeliverDate date,
    @OrderMessage varchar(100), 
    @OrderDate date, 
    @Vase bit, 
    @OrderCost decimal(6,2)
AS
BEGIN
    -- SET NOCOUNT ON added to prevent extra result sets from
    -- interfering with SELECT statements.
    SET NOCOUNT ON;

    DECLARE @flower int;

    SELECT @flower = Arr.FlowerID
    FROM Arrangements Arr
    WHERE FlowerName = @FlowerName

    DECLARE @AddID int;
    SELECT @AddID = coalesce((SELECT MAX(AddressID) + 1 FROM Addresses), 1)

    DECLARE @PhoneID int;
    SELECT @PhoneID = coalesce((SELECT MAX(PhoneID) + 1 FROM Phone), 1)

    DECLARE @CustID int;
    SELECT @CustID = coalesce((SELECT MAX(CustomerID) + 1 FROM Customers), 1)

    DECLARE @Del int;
    SELECT @Del = coalesce((SELECT MAX(DeliveryID) + 1 FROM Delivery), 1)

    DECLARE @Ords int;
    SELECT @Ords = coalesce((select max(StatusID) + 1 from OrderStatus), 1)

    DECLARE @Ord int;
    SELECT @Ord = coalesce((select max(OrderID) + 1 from Orders), 1)

    INSERT INTO Addresses (Street, City, States, Zip)
    VALUES (@Street, @City, @State, @Zip)

    SET @AddId = SCOPE_IDENTITY()

    INSERT INTO Phone (Phone)
    VALUES (@Phone)

    SET @PhoneID = SCOPE_IDENTITY()

    INSERT INTO Customers (AddressID, PhoneID, FirstName, LastName)
    VALUES (SCOPE_IDENTITY(), SCOPE_IDENTITY(), @FirstName, @LastName)

    SET @CustID = SCOPE_IDENTITY()

    INSERT INTO Delivery (DeliverDate)
    VALUES (@DeliverDate)

    SET @Del = SCOPE_IDENTITY()

    INSERT INTO OrderStatus (OrderStatus)
    VALUES (@OrderStatus)

    SET @Ords = SCOPE_IDENTITY()

    INSERT INTO Orders ([CustomerID], [FlowerID], [StatusID],[DeliveryID], OrderMessage, OrderDate, OrderCost, Vase)
    VALUES (SCOPE_IDENTITY(), @flower, SCOPE_IDENTITY(), SCOPE_IDENTITY(), @OrderMessage, @OrderDate, @OrderCost, @Vase)

    SET @Ord = SCOPE_IDENTITY()
END
GO

EXEC insertintoorders @Street = '555 LANE', @City='Somewhere', @State = 'XX', @Zip = '99999', @Phone = '1234567896', @FlowerName = 'The Flower of Love', @FirstName = 'George', 
@LastName = 'Fish', @DeliverDate = '10/10/2016', @OrderStatus = 'Completed', @OrderMessage = 'Fishy flowers', @OrderDate = '03/03/2016', @OrderCost = '200', @Vase = '1'

虽然我已经阅读了错误，但我不了解如何解决这些错误或者为什么他们在那里。

Answer 1

您正在使用IDENTITY_INSERT并为PhoneId和AddressId插入自己的值。 SCOPE_IDENTITY()始终是插入标识列的最后一个值，因此在插入手机后，它将返回PhoneId，而不是AddId。

选项1：使用您拥有的值。这是一个坏主意，因为如果你同时做两个添加，你可能会遇到冲突

SET IDENTITY_INSERT dbo.Customers ON
INSERT INTO Customers (CustomerID,AddressID,PhoneID,FirstName,LastName)
VALUES (@CustID, @AddId, @PhoneId ,@FirstName, @LastName)
SET IDENTITY_INSERT dbo.Customers OFF

选项2：让系统设置身份值并在每次插入后获取它们，即：

INSERT INTO Addresses (Street, City, States, Zip)
VALUES (@Street,@City,@State,@Zip)
SET @AddId = SCOPE_IDENTITY()

SQL Server存储过程具有多个表插入

1 个答案: