如何在弹簧中验证请求参数键

时间:2016-03-06 04:48:46

标签: java spring-mvc

我是春天新手。只想知道我们可以验证请求参数密钥。 我已经使用了RequestParam,因为例如@RequestParam(value= "sourceType")此处value = "sourceType"是我的密钥,因此如果用户输入的sourcety与给定的密钥不匹配,则会400 404 1}}错误,url中缺少sourceType。而不是给出@Scope("request") @RestController public class GetOperatorSeries{ @RequestMapping(value = "test", method = RequestMethod.GET) public String getOperatorSeries(HttpServletResponse response, @RequestParam(value = "mobno") long mobno, @RequestParam(value = "sourceType") String sourceType, @RequestParam(value = "responseType") String responseType) { } 错误,我希望它只在url或无效的sourceType中丢失sourceType? 这是我的控制器,

web.xml

这是我的<?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee" xmlns:web1="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="voiceBank" version="2.5"> <session-config> <session-timeout>60</session-timeout> </session-config> <servlet> <servlet-name>testmemspring</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>testmemspring</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/testmemspring-servlet.xml </param-value> </context-param> 文件

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:security="http://www.springframework.org/schema/security"
    xmlns:tx="http://www.springframework.org/schema/tx" xmlns:util="http://www.springframework.org/schema/util"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
        http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-3.1.xsd
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">

    <context:component-scan base-package="com.one97.org" />
    <context:annotation-config />
    <mvc:annotation-driven />

    <bean id="testSpring" class="com.one97.org.controller.TestSpring"
        scope="request">
    </bean>



    <bean id="internalViewResolver"
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/" />
        <property name="suffix" value=".jsp" />
        <property name="order" value="1" />
    </bean>




</beans>

这是我的弹簧配置文件

$.post( "check.php", { user: $("#username").val() }, function (data){
  if(data=='1'){
   //do 1
  }
  elseif(data=='0'){
    //do 0
  }
});

1 个答案:

答案 0 :(得分:0)

您可以将请求参数声明为可选。然后您可以手动检查它是否存在。根据它,您可以显示自定义错误消息。例如 -

@Scope("request")
@RestController
public class GetOperatorSeries{
@RequestMapping(value = "test", method = RequestMethod.GET)
    public String getOperatorSeries(HttpServletResponse response, @RequestParam(value = "mobno") long mobno,
            @RequestParam(value = "sourceType", required=false) String sourceType,
            @RequestParam(value = "responseType") String responseType, Model model)
{

    if (sourceType == null) {
     model.addAttribute("errorMessage", "Source Type is missing");
     return "viewName"; // Now show the error message in view. You can also add this error as flash attribute. You can also show a new error page.


    }

}