更改表单提交按钮的值,表示在表单提交后提交

时间:2016-03-06 04:35:37

标签: php html html5 forms submit

我的网站上有联系表格。我想更改提交按钮的文字,说“&34;已提交"表单成功提交后,甚至可以说它提交"提交"表格正在提交。我不确定如何做到这一点,我可以做一个改变文本的onclick事件,但不是我想要采取的路由,因为消息可能无法发送,按钮仍然会说提交。

这是我的表单

的html
<form method="post" action="contact.php">
    <input type="text" name="name" placeholder="Name"><br>
    <input type="email" name="email" placeholder="Email"><br>
    <textarea rows="8" cols="65" name="message"placeholder="Message"></textarea><br>
    <input id="submit" type="submit" name="submit" value="Let's Get In Touch">
</form>

这是我的PHP代码:

<?php

    $name = $_POST['name'];
    $email = $_POST['email'];
    $message = $_POST['message'];
    $from = 'From: Portfolio Website'; 
    $to = 'kyle.a.binger@gmail.com'; 
    $subject = 'Message From Personal Site';

    $body = "From: $name\n E-Mail: $email\n Message:\n $message";

    if ($_POST['submit']) {
        if (mail ($to, $subject, $body, $from)) { 
            echo '<p>Your message has been sent!</p>';
        } else { 
            echo '<p>Something went wrong, go back and try again!</p>'; 
        }
    }
?>

有没有办法用我现有的PHP代码执行此操作?提前感谢您的帮助。

2 个答案:

答案 0 :(得分:0)

您需要的是将数据传递给php脚本,并在不离开页面的情况下返回某些内容/ echo。

了解AJAX。你将能够做到这一点。 Here's a link to one of the first posts on stackoverflow that showed up. Here's a link to w3schools to give you a quick example/idea.

答案 1 :(得分:0)

如果您不想使用AJAX并且您要发布到页面本身,则可以执行以下操作

<form method="post" action=""> <!-- removed the PHP file name to post to itself -->
    <input type="text" name="name" placeholder="Name"><br>
    <input type="email" name="email" placeholder="Email"><br>
    <textarea rows="8" cols="65" name="message"placeholder="Message">  </textarea><br>
    <?php
        if (isset($_POST['submit'])) {
        echo '<input id="submit" type="button" name="submit" value="Submitted">'; //Changed type submit to button
        } else {
        echo '<input id="submit" type="submit" name="submit" value="Let\'s Get In Touch">';
        }
    ?>
</form>

<?php
    $name = $_POST['name'];
    $email = $_POST['email'];
    $message = $_POST['message'];
    $from = 'From: Portfolio Website';
    $to = 'kyle.a.binger@gmail.com';
    $subject = 'Message From Personal Site';

    $body = "From: $name\n E-Mail: $email\n Message:\n $message";

    if ($_POST['submit']) {
        if (mail ($to, $subject, $body, $from)) {
            echo '<p>Your message has been sent!</p>';
        } else {
            echo '<p>Something went wrong, go back and try again!</p>';
        }
    }
?>