Question

我有一张像这样的表order_details

 id |  SKU  |  quantity_purchased | discount_price
---------------------------------------------------
1   | abc   |   1                 |     10.0
2   | abc   |   90                |     00
2   | abc   |   9                 |     00
3   | xyz   |   1                 |     50.0
3   | xyz   |   2                 |     50.0
4   | xyz   |   100               |     00
4   | xyz   |   100               |     00
-----------------------------------------------

我的查询是

select 
(select sum(quantity_purchased)  from order_details where discount_price > 0.00) as qty_discount,
(select sum(quantity_purchased)  from order_details where discount_price = 0.00)as qty_original,
sku
from order_details
GROUP BY sku

我的要求是

  SKU   |  quantity_original | quantity_discount
---------------------------------------------------
 abc    |   1                 |     99
 xyz    |   3                 |     200
-----------------------------------------------

也就是说，计算后我需要两列相同的sku，

我无法建立逻辑，我尝试在嵌套查询中使用GROUP BY，但它不起作用...... 任何帮助都非常感谢.. 感谢

更新：试图通过这个但仍然失败，

select 
(select sum(quantity_purchased)  from order_details where discount_price > 0.00 ) as qty_discount,
(select sum(quantity_purchased)  from order_details where discount_price = 0.00 )as qty_original,
sku
from order_details
where sku = (select distinct sku from order_details)
GROUP BY sku

Answer 1

您可以使用conditional aggregation：

select sku, 
       sum(case when discount_price != 0 then quantity_purchased 
                else 0 
           end) quantity_original,
       sum(case when discount_price = 0 then quantity_purchased 
                else 0 
           end) quantity_discount
from order_details
group by sku

SQL Fiddle Demo

Results:

| SKU | quantity_original | quantity_discount |
|-----|-------------------|-------------------|
| abc |                 1 |                99 |
| xyz |                 3 |               200 |

嵌套查询返回值

1 个答案: