在字符＆＃34;？＆＃34;之前获取当前URL

Question

我想知道如何在?字符之前获取当前网址：

http://www.example.com/pag1?q=ok

输出：

http://www.example.com/pag1

Answer 1

你可以将你的网址分解为

$url = 'http://www.example.com/pag1?q=ok';

$explodedURL= parse_url($url);

echo '<pre>';
print_r($explodedURL['host'].explodedURL['path']);

echo $explodedURL['scheme'].'://'.$explodedURL['host'].$explodedURL['path'];

输出：

Array
(
[scheme] => http
[host] => www.example.com
[path] => /pag1
[query] => q=ok
)
http://www.example.com/pag1

Answer 2

类似的东西：

$url = 'http://www.example.com/pag1?q=ok’;
$pos = strpos($url, '?');
$yourstr = strstr($url, 0, $pos - 1);