自动完成功能,按属性搜索json对象

时间:2016-03-05 09:55:48

标签: javascript jquery json autocomplete

假设我有以下json对象,其中包含有关一组人的信息。

data=[{id:2, fname:"bob", lname:"roberts", common_name:null, email:"sideshowbob@email.com", telephone:"555-555-5555", street:"333 Street St", city:"Salt Lake City", state:"UT", country:null, zip:"99999", dynamid:null, notes:null, director:false, contractor:false, contractor_need_agreement:false, shareholder:false, shares_held:0, company_id:1, created_at:"2016-02-23T10:15:09.339Z", updated_at:"2016-02-23T10:15:09.339Z", officer:false, snapshot:null, sign_term_voting:false, drag_liquidation_approval:false, rofr_consenter:false, investor_councel:false, ir_insured:false, issuer_signing_officer:false, issuer_registered_agent:false, issuer_councel:false, rep_lead_investor:false, rep_investor:false, rep_founder:false}, 
      {id:1, fname:"John", lname:"Smith", common_name:null, email:"john.smith@email.com", telephone:"555-555-5555", street:"333 Street St", city:"Salt Lake City", state:"UT", country:null, zip:"99999", dynamid:null, notes:null, director:false, contractor:false, contractor_need_agreement:false, shareholder:false, shares_held:0, company_id:1, created_at:"2016-02-23T10:15:09.327Z", updated_at:"2016-02-23T10:15:09.327Z", officer:false, snapshot:null, sign_term_voting:false, drag_liquidation_approval:false, rofr_consenter:false, investor_councel:false, ir_insured:false, issuer_signing_officer:false, issuer_registered_agent:false, issuer_councel:false, rep_lead_investor:false, rep_investor:false, rep_founder:false}]

现在我想在文本框中实现某种自动完成功能,搜索每个人的姓名(即fname+" "+lname)寻找匹配项。在找到匹配后,它将返回找到匹配的人或该人的ID。

我在开始这方面遇到了一些麻烦。我想我可以写出来,我用keyup触发循环通过对象,显示匹配字符串的名称,并在点击其中一个时返回相应的索引,但这似乎是我重新发明轮子。

是否有一种有效/最佳实践方式来提取此类功能?

1 个答案:

答案 0 :(得分:1)

来自此typeahead.js演示here

jsfiddle上的完整代码:

var substringMatcher = function(strs) {
  return function findMatches(q, cb) {
    var matches, substringRegex;

    matches = [];

    substrRegex = new RegExp(q, 'i');

    $.each(strs, function(i, str) {
      var fullname = str.fname + " " + str.lname
            console.log(fullname);

      if (substrRegex.test(fullname)) {
        matches.push(fullname);
      }
    });

    cb(matches);
  };
};