具有模拟数据的ModelChoiceField的UnitTest ModelForm

时间:2016-03-05 05:30:03

标签: python django unit-testing modelform

我一直在尝试为我的ModelForm编写单元测试,它有一个ModelChoiceField。我正在使用模拟数据创建Form实例。

这是我的模特:

# models.py
class Menu(models.Model):
    dish = models.ForeignKey(Dish, default=None)
    price = models.DecimalField(max_digits=7, decimal_places=2)

# forms.py
class MenuForm(forms.ModelForm):
    class Meta:
        model = Menu
        fields = ('dish', 'price',)

    def clean(self):
        cleaned_data = super(MenuForm, self).clean()
        price = cleaned_data.get('price', None)
        dish = cleaned_data.get('dish', None)

        # Some validation below
        if price < 70:
            self.add_error('price', 'Min price threshold')
            return cleaned_data

这是我的测试用例:

class MenuFormTest(TestCase):
    def test_price_threshold(self):
        mock_dish = mock.Mock(spec=Dish)
        form_data = {
            'dish': mock_dish,
            'price': 80,
        }
        form = forms.MenuForm(data=form_data)
        self.assertTrue(form.is_valid())

此操作失败,并显示以下错误:

<ul class="errorlist"><li>dish<ul class="errorlist"><li>Select a valid choice. That choice is not one of the available choices.</li></ul></li></ul>

如何避免抛出该错误。 form.is_valid()应该True。有没有办法可以修补ModelChoiceField's queryset?我尝试修补表单的dish字段clean()方法,如下所示:

form = forms.MenuForm(data=form_data)
dish_clean_patcher = mock.patch.object(form.fields['dish'], 'clean')
dish_clean_patch = dish_clean_patcher.start()
dish_clean_patch.return_value = mock_dish

self.assertTrue(form.is_valid())

然后看起来,它在将表单数据保存到_post_clean()方法中的模型实例时失败了。这是追溯:

Traceback (most recent call last):
  File "/home/vagrant/venv/local/lib/python2.7/site-packages/mock/mock.py", line 1305, in patched
    return func(*args, **keywargs)
  File "/vagrant/myapp/tests/test_forms.py", line 51, in test_price_threshold
    self.assertFalse(form.is_valid())
  File "/home/vagrant/venv/local/lib/python2.7/site-packages/django/forms/forms.py", line 185, in is_valid
    return self.is_bound and not self.errors
  File "/home/vagrant/venv/local/lib/python2.7/site-packages/django/forms/forms.py", line 177, in errors
    self.full_clean()
  File "/home/vagrant/venv/local/lib/python2.7/site-packages/django/forms/forms.py", line 396, in full_clean
    self._post_clean()
  File "/home/vagrant/venv/local/lib/python2.7/site-packages/django/forms/models.py", line 427, in _post_clean
    self.instance = construct_instance(self, self.instance, opts.fields, construct_instance_exclude)
  File "/home/vagrant/venv/local/lib/python2.7/site-packages/django/forms/models.py", line 62, in construct_instance
    f.save_form_data(instance, cleaned_data[f.name])
  File "/home/vagrant/venv/local/lib/python2.7/site-packages/django/db/models/fields/__init__.py", line 874, in save_form_data
    setattr(instance, self.name, data)
  File "/home/vagrant/venv/local/lib/python2.7/site-packages/django/db/models/fields/related.py", line 632, in __set__
    instance._state.db = router.db_for_write(instance.__class__, instance=value)
  File "/home/vagrant/venv/local/lib/python2.7/site-packages/django/db/utils.py", line 300, in _route_db
    if instance is not None and instance._state.db:
  File "/home/vagrant/venv/local/lib/python2.7/site-packages/mock/mock.py", line 716, in __getattr__
    raise AttributeError("Mock object has no attribute %r" % name)
AttributeError: Mock object has no attribute '_state'

我该如何避免这一部分?我不希望它完全关注instance._state.db

我是否正确测试了表格?或者我应该通过完全修补form.is_valid()方法而不是致电form.clean()来调用super(MenuForm, self).clean()方法,并检查form.errors

2 个答案:

答案 0 :(得分:7)

我想说调用form.is_valid()是测试表单的好方法。我不确定嘲笑模型。

Internally the form is calling get_limit_choices_to on your dish field(Django目前正在为您创建)。

You would need to mock the dish field's .queryset or get_limit_choices_to here,(或调用堆栈中的其他位置使得值在这里毫无意义)以某种方式实现您想要的。

或者,在测试中创建Dish并让Django的内部继续做他们正在做的事情会更简单。

class MenuFormTest(TestCase):
    def test_price_threshold(self):
        dish = Dish.objects.create(
            # my values here
        )
        form_data = {
            'dish': dish.id,
            'price': 80,
        }
        form = MenuForm(data=form_data)
        self.assertTrue(form.is_valid())

如果您真的没有使用Django的测试数据库,那么一种策略可能是模拟MenuForm.cleanMenuForm._post_clean

class MenuFormTest(TestCase):
    def test_price_threshold(self):
        mock_dish = mock.Mock(spec=Dish)
        form_data = {
            'dish': 1,
            'price': 80,
        }
        form = MenuForm(data=form_data)
        form.fields['dish'].clean = lambda _: mock_dish
        form._post_clean = lambda : None
        self.assertTrue(form.is_valid())

如果你打算这样做,你需要问问自己你的目标是什么。

答案 1 :(得分:0)

如果认为你的考试不是&#34;单位&#34;足够多。你似乎想测试价格门槛吗?也许你可以这样做:

# forms.py
class MenuForm(forms.ModelForm):
    class Meta:
        model = Menu
        fields = ('dish', 'price',)

    def clean(self):
        cleaned_data = super(MenuForm, self).clean()
        price = cleaned_data.get('price', None)
        dish = cleaned_data.get('dish', None)

        # Some validation below
        if not self._is_price_valid(price):
            self.add_error('price', 'Min price threshold')
            return cleaned_data

    def _is_price_valid(self, price):
        return price >= 70

你的考试:

class MenuFormTest(TestCase):
    def test_price_threshold(self):
        form = forms.MenuForm()
        self.assertTrue(form._is_price_valid(80))

我同意,对于这个例子来说,它有点过分&#34;过度使用&#34;只是添加一个方法ta返回一个简单的比较,但如果你只是想测试价格门槛而不打扰Django内部的表单验证过程,那么隔离它就不错了