SQL Server 2000中是否可以使用以下命令?
CREATE FUNCTION getItemType (@code varchar(18))
RETURNS int
AS
BEGIN
Declare @Type tinyint
Select @Type = case len(@code)
WHEN 12,14,17 THEN 1
WHEN 13,15,18 THEN 2
WHEN 8,10 THEN 3
ELSE 0
END
RETURN (@Type)
END
感谢。
答案 0 :(得分:6)
这应该这样做:
CREATE FUNCTION getItemType(@code VARCHAR(18))
RETURNS INT
AS
BEGIN
RETURN CASE
WHEN LEN(@code) IN (12,14,17) THEN 1
WHEN LEN(@code) IN (13,15,18) THEN 2
WHEN LEN(@code) IN (8,100) THEN 3
ELSE 0
END
END
答案 1 :(得分:4)
试试这个:
Select @Type =
(select case
WHEN len(@code) IN (12,14,17) THEN 1
WHEN len(@code) IN (13,15,18) THEN 2
WHEN len(@code) IN (8,10) THEN 3
ELSE 0
END)
答案 2 :(得分:0)
try
SELECT CASE
WHEN LEN(@gcode) IN(x, y, z) THEN a
END
etc.
或者您可能需要
SELECT CASE LEN(@gcode)
WHEN x THEN a
WHEN y THEN a
END
等