我正在尝试为现有代码添加代码。我有两个xmls以下:
Out.xml
<School>
<Classes>
<Class>
<Students>
<Student SequenceNumber="1">
<ID>123</ID>
<Name>AAA</Name>
</Student>
</Students>
</Class>
</Classes>
</School>
In.xml
<School>
<Classes>
<Class>
<Students>
<Student SequenceNumber="1">
<ID>456</ID>
<Name>BBB</Name>
</Student>
<Student SequenceNumber="2">
<ID>123</ID>
<Name>AAA</Name>
</Student>
<Student SequenceNumber="3">
<ID>789</ID>
<Name>CCC</Name>
</Student>
</Students>
</Class>
</Classes>
</School>
现在我需要检查Out.xml和In.xml,我的最终Out.xml必须如下所示。这里的规则是在Out和In xmls中检查StudentID。如果Out xml没有它,并且在xml中它将它添加到已存在元素末尾的Out.xml。
Out.xml
<School>
<Classes>
<Class>
<Students>
<Student SequenceNumber="1">
<ID>123</ID>
<Name>AAA</Name>
</Student>
<Student SequenceNumber="2">
<ID>456</ID>
<Name>BBB</Name>
</Student>
<Student SequenceNumber="3">
<ID>789</ID>
<Name>CCC</Name>
</Student>
</Students>
</Class>
</Classes>
</School>
现有代码如下
string inFileName = @"C:\In.xml";
string inXml = System.IO.File.ReadAllText(inFileName);
var xmlReaderSource = XmlReader.Create(new StringReader(inXml));
var mgr = new XmlNamespaceManager(xmlReaderSource.NameTable);
mgr.AddNamespace("m", "http://www.mismo.org/residential/2009/schemas");
XDocument sourceXmlDoc = XDocument.Load(xmlReaderSource);
string outFileName = @"C:\Out.xml";
string outXml = System.IO.File.ReadAllText(outFileName);
XmlDocument targetXmlDoc = new XmlDocument();
targetXmlDoc.LoadXml(outXml);
我现在无法更改上面的代码我需要添加逻辑。
我添加如下
string xpath = @"/m:School/m:Classes/m:Class/m:Students";
XmlNodeList outStudentNodes = targetXmlDoc.SelectNodes(xpath + "/m:Student", namespaceManager);
if(outStudentNodes== null || outStudentNodes.Count <= 0)
{
return;
}
XElement root = sourceXmlDoc.Root;
IEnumerable<XElement> inStudentsColl = from item in root.Elements("Classes").Descendants("Class")
.Descendants("Students").Descendants("Student")
select item;
现在我有了XmlNodeList和IEnumerble,试图看看我是否可以使用LINQ语句并使代码变得简单。
节点:我不是在问如何使用C#添加节点/元素。我正在寻找如何比较两个xmls然后将节点/元素添加到缺少那些节点/元素的那个节点/元素。我的问题是一个xml被读取像XDocument和其他使用XmlDocument。
更新
非常感谢@TheAnatheme。对此,我真的非常感激。
我遵循了TheAnatheme建议我并且它有效。我将TheAnatheme的答案标记为真正的解决方案。请参阅下面我在foreach块中所做的事情,这样如果有人想使用它们可以参考这篇文章。
string xpath = @"/m:School/m:Classes/m:Class/m:Students
XmlNode studentsNode = targetXmlDoc.SelectSingleNode(xpath, namespaceManager);
foreach (var element in elementsToAdd)
{
//Add Microsoft.CSharp.dll (if needed ) to your project for below statement to work
dynamic studentElement = element as dynamic;
if (studentElement != null)
{
XmlElement studentXmlElement = targetXmlDoc.CreateElement("Student");
XmlElement studentIDXmlElement = targetXmlDoc.CreateElement("ID");
studentIDXmlElement.InnerText = studentElement.ID;
XmlElement studentNameXmlElement = targetXmlDoc.CreateElement("Name");
studentNameXmlElement .InnerText = studentElement.Name;
studentXmlElement.AppendChild(studentIDXmlElement);
studentXmlElement.AppendChild(studentNameXmlElement);
studentsNode.AppendChild(childElement);
}
}
答案 0 :(得分:1)
这会将两个集合都设置为一个匿名对象List,进行比较,并为您提供一组尚不存在的匿名对象,您可以将这些对象添加到out xml中。
public static List<object> GetInStudents(XDocument sourceXmlDoc)
{
IEnumerable<XElement> inStudentsElements =
sourceXmlDoc.Root.Elements("Classes").Descendants("Class")
.Descendants("Students").Descendants("Student");
return inStudentsElements.Select(i =>
new { Id = i.Elements().First().Value,
Name = i.Elements().Last().Value }).Cast<object>().ToList();
}
public static List<object> GetOutStudents(XmlDocument targetXmlDoc)
{
XmlNodeList outStudentsElements = targetXmlDoc.GetElementsByTagName("Students")[0].ChildNodes;
var outStudentsList = new List<object>();
for (int i = 0; i < outStudentsElements.Count; i++)
{
outStudentsList.Add(new { Id = outStudentsElements[i].ChildNodes[0].InnerText,
Name = outStudentsElements[i].ChildNodes[1].InnerText });
}
return outStudentsList;
}
你比较它们:
var inStudents = GetInStudents(sourceXmlDoc);
var outStudents = GetOutStudents(targetXmlDoc);
if (inStudents.SequenceEqual(outStudents))
{
return;
}
else
{
var elementsToAdd = inStudents.Except(outStudents);
foreach (var element in elementsToAdd)
{
// create xmlNode with element properties, add element to xml
}
}