std :: stol在失败时损坏堆栈

Question

class.h

// class.h
#pragma once
#include <string>
#include <iostream>

class TV {
public:
  TV() {}
  TV(std::string, std::string, std::string, std::string, std::string);

private:
  int member;
};

main.cpp中：

//main.cpp
#include "class.h"    

TV::TV(std::string a, std::string b, std::string c, std::string d, std::string e) {
  try {
    member = std::stol(a);
    if (member <= 0)
      throw;
  }
  catch (...) {
    std::cout << "Invalid argument" << std::endl;
  }
}


int main(int argc, char *argv[]) {
  new TV("TEST","NAME","0.1","0.1","0.1");
};

事实证明，如果我为std :: stol提供了invalid_argument，那么在gdb中传递给该函数的所有其他参数都会显示为已损坏。

有人可以解释为什么会这样吗？