我有一个简单的双屏应用程序。第一个屏幕向用户显示登录选项,第二个屏幕是他们在登录时看到内容的位置。
用户登录后,我将密钥设置为Flow.get( view ).set( Screens.CHAT )
。
一切都很好,花花公子但我遇到的问题让我的观点看起来像这样:
当用户通过按下主页按钮离开应用程序然后返回到它(基本上在onRestart( )
之后)时,会重新绘制视图。未填充的RecyclerView
将再次添加到视图层次结构中。
我的Dispatcher
逻辑是:
public void dispatch(Traversal traversal, TraversalCallback callback) {
Object dest = traversal.destination.top();
Object source = traversal.origin == null ? null : traversal.origin.top();
ViewGroup root = (ViewGroup) activity.findViewById(R.id.root);
if (traversal.origin != null) {
int childCount = root.getChildCount();
// Our container has a root view with an ImageView in it.
// If child count > 1, we need to remove the child at position = 1
// because ImageView is at position = 0
if (childCount > 1) {
// save state
traversal.getState(traversal.origin.top()).save(root.getChildAt(1));
// remove the added views
removeAllViewsAfter(root,0);
}
}
@LayoutRes int layout;
if(dest.equals(Screens.WELCOME)){
layout = R.layout.view_welcome;
}else if(dest.equals(Screens.CHAT)){
layout = R.layout.view_chat;
}else{
throw new IllegalArgumentException("Unrecognized Screen");
}
View incomingView = LayoutInflater
.from(traversal.createContext(dest, activity))
.inflate(layout, root, false);
traversal.getState( traversal.destination.top() ).restore(incomingView);
root.addView( incomingView );
callback.onTraversalCompleted();
}
//----------------------------------------------------------------------------------------------
private void removeAllViewsAfter(ViewGroup root, int index){
for( int i = root.getChildCount() - 1; i > index; i-- ){
root.removeViewAt( i );
}
}
//----------------------------------------------------------------------------------------------
我在Dispatcher
逻辑中做了哪些更改,以避免相同的布局被夸大并再次添加?
答案 0 :(得分:0)
问题是您的root
ViewGroup 未被清除。
我相信这会解决您的问题(<
删除,>
添加)。
12c12
< if (childCount > 1) {
---
> if (childCount > 0) {
14c14
< traversal.getState(traversal.origin.top()).save(root.getChildAt(1));
---
> traversal.getState(traversal.origin.top()).save(root.getChildAt(0));
16c16
< removeAllViewsAfter(root,0);
---
> frame.removeAllViews();
36,42d35
< //----------------------------------------------------------------------------------------------
< private void removeAllViewsAfter(ViewGroup root, int index){
< for( int i = root.getChildCount() - 1; i > index; i-- ){
< root.removeViewAt( i );
< }
< }
< //----------------------------------------------------------------------------------------------
Flow repo对您已有的内容有example with something pretty close。
@Override
public void dispatch(@NonNull Traversal traversal, @NonNull TraversalCallback callback) {
Log.d("BasicDispatcher", "dispatching " + traversal);
Object destKey = traversal.destination.top();
ViewGroup frame = (ViewGroup) activity.findViewById(R.id.basic_activity_frame);
// We're already showing something, clean it up.
if (frame.getChildCount() > 0) {
final View currentView = frame.getChildAt(0);
// Save the outgoing view state.
if (traversal.origin != null) {
traversal.getState(traversal.origin.top()).save(currentView);
}
// Short circuit if we would just be showing the same view again.
final Object currentKey = Flow.getKey(currentView);
if (destKey.equals(currentKey)) {
callback.onTraversalCompleted();
return;
}
frame.removeAllViews();
}
@LayoutRes final int layout;
if (destKey instanceof HelloScreen) {
layout = R.layout.hello_screen;
} else if (destKey instanceof WelcomeScreen) {
layout = R.layout.welcome_screen;
} else {
throw new AssertionError("Unrecognized screen " + destKey);
}
View incomingView = LayoutInflater.from(traversal.createContext(destKey, activity)) //
.inflate(layout, frame, false);
frame.addView(incomingView);
traversal.getState(traversal.destination.top()).restore(incomingView);
callback.onTraversalCompleted();
}