Display digits individually

Question

I am having trouble with the following question...

"write a method displayDigits that receives an integer between 1 and 99999 and displays it as a sequence of digits, separating each pair of digits by two spaces. For example, the integer 4562 should appear as 4 5 6 2"

This is what I have currently, I know it displays the numbers backwards, but won't compile with a "error: missing return statement" error.

public static int displayDigits(int num1)
{
    for (int i=0; num1>0; i++)
    {
        return(num1 % 10)
    }
}

The book noted that we only use % and / to solve the problem. Help please!! I've been working on this for hours...

Answer 1

AppCompatDelegate.setDefaultNightMode(AppCompatDelegate.MODE_NIGHT_YES);

Answer 2

public static void displayDigits(int num1) {
    String result = "";
    for (int i=0; num1>0; i++) {
        if(i>0) result = " " + result;
        result = num1%10 + result;
        num1 /= 10;
    }
    System.out.println(result);
}

Answer 3

Do following:

String resultNumber = "";
for(int i = 0; i < num1.toString().length(); i++)
    resultNumber += num1.toString().substring(i, i+1) + " ";
resultNumber = resultNumber.substring(0, resultNumber.length() - 2);

When num1 is 4564, then resultNumber is "4 5 6 4" and that works for any number (between min and max value of integer)