Question

我正在尝试在工作区中读取文件。该文件是在上一步中创建的（通过对java脚本的shell脚本调用）。我确认它存在。我正在使用＆＃39; readFile＆＃39;。我在下面得到了例外。我可以在shell脚本中访问这个文件，但我想做一些json解析，而且更喜欢使用groovy。这里有一些安全措施阻止访问吗？

java.io.FileNotFoundException: /var/lib/jenkins/jobs/MBTest/branches/develop/workspace/functional-tests/target/scalatestcuke-F63QUALZN4.json
(No such file or directory)
at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(FileInputStream.java:146)
at hudson.FilePath.read(FilePath.java:1751)
at org.jenkinsci.plugins.workflow.steps.ReadFileStep$Execution.run(ReadFileStep.java:87)
at org.jenkinsci.plugins.workflow.steps.ReadFileStep$Execution.run(ReadFileStep.java:81)
at org.jenkinsci.plugins.workflow.steps.AbstractSynchronousNonBlockingStepExecution$1$1.call(AbstractSynchronousNonBlockingStepExecution.java:49)
at hudson.security.ACL.impersonate(ACL.java:213)
at org.jenkinsci.plugins.workflow.steps.AbstractSynchronousNonBlockingStepExecution$1.run(AbstractSynchronousNonBlockingStepExecution.java:47)
at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:471)
at java.util.concurrent.FutureTask.run(FutureTask.java:262)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
at java.lang.Thread.run(Thread.java:745)

Jenkins文件（略微减少）

#!groovy
// Execute the following steps on the master


node {

 stage name: 'Checkout', concurrency: 1

 checkout scm
 functionalTest()
 release()
}


def functionalTest(){

 stage name: 'QA', concurrency: 1

 echo "nonrestF63"
 sh scalatestScript("F63QUALZN4","latest",5922,"-l jhc.TDRest")

 archive includes: 'functional-tests/target/*.json'

 def job = build job: 'generic-cucumber-report', parameters: [
   [$class: 'StringParameterValue', name: 'projectname', value:  'MBTest/develop'],
   [$class: 'StringParameterValue', name: 'jsondir', value: 'functional-tests/target']]

 step ([$class: 'CopyArtifact',
      projectName: 'generic-cucumber-report',
      filter: 'target/cucumber-html-reports/**/*',
      selector: [$class: 'SpecificBuildSelector', buildNumber: job.getId()]]);

 publishHTML(target: [allowMissing: false, keepAll: true, reportDir:   'target/cucumber-html-reports/', 
        reportFiles: 'feature-overview.html', reportName: 'Test results'])

def failures = countFailures()
if(failures > 0){
    error '${failures} test failures reported'
}
}

def countFailures() {
  sh "ls functional-tests/target/*.json | sed -e ':a' -e 'N' -e '\$!ba' -e 's/\\n/,/g' > filelist.txt"
  def txt = readFile "filelist.txt"
  def count = 0
  txt.split(",") each { jsonFile ->
    def text = readFile jsonFile
    def json = new groovy.json.JsonSlurper().parseText(text) 
    count = count + countMatches(json,"status","failed")
  }
  return count
}

这个问题可以在countfailures方法中看到。我从WS中读取了一个文件列表，然后遍历这些名称。当我尝试阅读文件时，虽然我得到了FNF。

Answer 1

你可以使用这种代码安静，你将从当前版本中获得最新的人工制品。

step ([$class: 'CopyArtifact', projectName: 'Pipeline', filter: '**.txt', selector: [$class: 'SpecificBuildSelector', buildNumber: env.BUILD_NUMBER]])

Jenkins工作流 - 工作区文件

1 个答案: