Question

我正在寻找一种更有效的方法来组合这三个数组。两个数据阵列和一个连接两个数组的“交叉”数组。

3阵列

var drives = [
    {"drivesId": "rwd", "name": "RWD"},
    {"drivesId": "fwd", "name": "FWD"},
    {"drivesId": "awd", "name": "AWD"}
]


var cars = [
    {"carId": "civic", "name": "Civic"},
    {"carId": "wrx", "name": "WRX"},
    {"carId": "mustang", "name": "Mustang"},
    {"carId": "focus", "name": "Focus"},
]

var drivesXcars = [
    {"drivesXcars": "uid1", "carId": "civic", "drivesId": "fwd"},
    {"drivesXcars": "uid2", "carId": "wrx", "drivesId": "awd"},
    {"drivesXcars": "uid3", "carId": "mustang", "drivesId": "rwd"},
    {"drivesXcars": "uid4", "carId": "focus", "drivesId": "fwd"},
]

我希望将它们组合成一个看起来像这样的数组：

var carsComplete = [
    {"drivesId": "fwd", "driveName": "FWD", "cars": [
        {"carId": "civic", "name": "Civic"},
        {"carId": "focus", "name": "Focus"}
    ]},
    {"drivesId": "rwd", "driveName": "RWD", "cars": [
        {"carId": "mustang", "name": "Mustang"}
    ]},
    {"drivesId": "awd", "driveName": "AWD", "cars": [
        {"carId": "wrx", "name": "WRX"}
    ]},
]

是的，我可以做循环方式的标准，但是这些阵列变大了，标准的“暴力”方式对我来说还不够好。

我希望有人能够使用AngularJS和/或lodash知道更有效的方法。

Answer 1

可以通过简单的JavaScript轻松实现：

const carsComplete = drives.map(x => ({
  drivesId: x.drivesId,
  driveName: x.name,
  cars: drivesXcars
    // Only the cars which belong to this person.
    .filter(n => n.drivesId === x.drivesId) 
    // Get the car by id.
    .map(n => cars.find(m => m.carId === n.carId))
}))

请参阅JS Bin。

Answer 2

使用Underscore.js

的解决方案

var drivesXcarsGroup = _.groupBy(drivesXcars, "drivesId");
var carsComplete = drives.map(function(driver){
                            return {
                                "drivesId": driver.drivesId,
                                "driveName": driver.name,
                                "cars": drivesXcarsGroup[driver.name.toLowerCase()]
                               }
                           });

将三个阵列合并为一个

3阵列

2 个答案: