Question

我一直在研究一个程序来显示两个矩阵的减法结果。该程序允许用户输入矩阵的大小，然后提示用户输入这两个矩阵的值。最后，程序应该单独显示这两个矩阵，然后显示两个矩阵的减法结果。

目前，当代码运行时，输出只是无穷无尽的数字显示。我找不到创造这个问题的原因。对于导致此问题的原因，我将不胜感激。

谢谢！

using namespace std;

#include <iostream>
#include <conio.h>

int main(){
    int i = 0, j = 0, n=0, a[10][10], b[10][10], c[10][10];
    bool positive = false;

        cout << "Enter the size of the two - dimensional array: ";
        cin >> n;
        while (!positive){
            if (n >= 0){
                positive = true;
            }
            else {
                cout << "Please enter a positive number for the size of the matrix.";
                cin >> n;
            }
        }   
    cout << "Enter the values of the elements of array A" << endl;
    for (i = 0; i < n; i++){
        for (j = 0; j < n; j++){
            cin >> a[i][j];
        }
    }
    cout << "Enter the values of the elements of array B" << endl;
    for (i = 0; i < n; i++){
        for (j = 0; j < n; j++){
            cin >> b[i][j];
        }
    }
    cout << "Matrix A:" << endl;
    for (i = 0; i < n; i++){
        for (j = 0; i < n; j++){

            cout << a[i][j] << " ";
        }
    }
    cout << "Matrix B:" << endl;
    for (i = 0; i < n; i++){
        for (j = 0; j < n; j++){

            cout << b[i][j] << " ";
        }
        cout << "\n";   
    }
    for (i = 0; i < n; i++){
        cout << endl;
        for (j = 0; j < n; j++){
            c[i][j] = a[i][j] - b[i][j];

        }
        cout << "\n";   
    }
    cout << "Matrix A - Matrix B: " << endl;
    for (i = 0; i < n; i++){
        for (j = 0; j < n; j++){
            cout << c[i][j] << " ";
        }
        cout << "\n";
    }
    return 0;
}

Answer 1

这条线路可能会造成麻烦吗？

cout << "Matrix A:" << endl;
for (i = 0; i < n; i++){
    for (j = 0; i < n; j++){

        cout << a[i][j] << " ";
    }
}

改变j的for循环（即，j

矩阵减法无穷无尽的显示问题

1 个答案: