首先,我的问题与How do I convert image to 2-bit per pixel?不同,不幸的是,它的解决方案在我的案例中不起作用......
我需要将图像转换为每像素2位灰度BMP格式。示例图像具有以下属性:
Color Model: RGB
Depth: 4
Is Indexed: 1
Dimension: 800x600
Size: 240,070 bytes (4 bits per pixel but only last 2 bits are used to identify the gray scales as 0/1/2/3 in decimal or 0000/0001/0010/0011 in binary, plus 70 bytes BMP metadata or whatever)
3s表示图像开头的白色像素。再往下有一些0s,1s和2s代表黑色,深灰色和浅灰色:
使用以下命令,
convert pic.png -colorspace gray +matte -depth 2 out.bmp
我可以直观正确的4级灰度图像,但每个像素的深度或尺寸错误:
Color Model: RGB
Depth: 8 (expect 4)
Dimension: 800x504
Size: 1,209,738 bytes (something like 3 bytes per pixel, plus metadata)
(no mention of indexed colour space)
请帮忙......
答案 0 :(得分:3)
好的,我已经按照Mark的提示编写了一个Python脚本(参见原始问题下的评论),手动创建一个带有4bpp的4级灰度BMP。这种特定的BMP格式结构适用于WaveShare制造的4.3英寸电子纸显示模块。规格可以在这里找到:http://www.waveshare.com/wiki/4.3inch_e-Paper
以下是如何将原始图像传输到我的代码并保存结果。
convert in.png -colorspace gray +matte -colors 4 -depth 2 -resize '800x600>' pgm:- | ./4_level_gray_4bpp_BMP_converter.py > out.bmp
4_level_gray_4bpp_BMP_converter.py
的内容:
#!/usr/bin/env python
"""
### Sample BMP header structure, total = 70 bytes
### !!! little-endian !!!
Bitmap file header 14 bytes
42 4D "BM"
C6 A9 03 00 FileSize = 240,070 <= dynamic value
00 00 Reserved
00 00 Reserved
46 00 00 00 Offset = 70 = 14+56
DIB header (bitmap information header)
BITMAPV3INFOHEADER 56 bytes
28 00 00 00 Size = 40
20 03 00 00 Width = 800 <= dynamic value
58 02 00 00 Height = 600 <= dynamic value
01 00 Planes = 1
04 00 BitCount = 4
00 00 00 00 compression
00 00 00 00 SizeImage
00 00 00 00 XPerlPerMeter
00 00 00 00 YPerlPerMeter
04 00 00 00 Colours used = 4
00 00 00 00 ColorImportant
00 00 00 00 Colour definition index 0
55 55 55 00 Colour definition index 1
AA AA AA 00 Colour definition index 2
FF FF FF 00 Colour definition index 3
"""
# to insert File Size, Width and Height with hex strings in order
BMP_HEADER = "42 4D %s 00 00 00 00 46 00 00 00 28 00 00 00 %s %s 01 00 04 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 04 00 00 00 00 00 00 00 00 00 00 00 55 55 55 00 AA AA AA 00 FF FF FF 00"
BMP_HEADER_SIZE = 70
BPP = 4
BYTE = 8
ALIGNMENT = 4 # bytes per row
import sys
from re import findall
DIMENTIONS = 1
PIXELS = 3
BLACK = "0"
DARK_GRAY = "1"
GRAY = "2"
WHITE = "3"
# sample data:
# ['P5\n', '610 590\n', '255\n', '<1 byte per pixel for 4 levels of gray>']
# where item 1 is always P5, item 2 is width heigh, item 3 is always 255, items 4 is pixels/colours
data = sys.stdin.readlines()
width = int(data[DIMENTIONS].strip().split(' ')[0])
height = int(data[DIMENTIONS].strip().split(' ')[1])
if not width*height == len(data[PIXELS]):
print "Error: pixel data (%s bytes) and image size (%dx%d pixels) do not match" % (len(data[PIXELS]),width,height)
sys.exit()
colours = [] # enumerate 4 gray levels
for p in data[PIXELS]:
if not p in colours:
colours.append(p)
if len(colours) == 4:
break
# it's possible for the converted pixels to have less than 4 gray levels
colours = sorted(colours) # sort from low to high
# map each colour to e-paper gray indexes
# creates hex string of pixels
# e.g. "0033322222110200....", which is 4 level gray with 4bpp
if len(colours) == 1: # unlikely, but let's have this case here
pixels = data[PIXELS].replace(colours[0],BLACK)
elif len(colours) == 2: # black & white
pixels = data[PIXELS].replace(colours[0],BLACK)\
.replace(colours[1],WHITE)
elif len(colours) == 3:
pixels = data[PIXELS].replace(colours[0],DARK_GRAY)\
.replace(colours[1],GRAY)\
.replace(colours[2],WHITE)
else: # 4 grays as expected
pixels = data[PIXELS].replace(colours[0],BLACK)\
.replace(colours[1],DARK_GRAY)\
.replace(colours[2],GRAY)\
.replace(colours[3],WHITE)
# BMP pixel array starts from last row to first row
# and must be aligned to 4 bytes or 8 pixels
padding = "F" * ((BYTE/BPP) * ALIGNMENT - width % ((BYTE/BPP) * ALIGNMENT))
aligned_pixels = ''.join([pixels[i:i+width]+padding for i in range(0, len(pixels), width)][::-1])
# convert hex string to represented byte values
def Hex2Bytes(hexStr):
hexStr = ''.join(hexStr.split(" "))
bytes = []
for i in range(0, len(hexStr), 2):
byte = int(hexStr[i:i+2],16)
bytes.append(chr(byte))
return ''.join(bytes)
# convert integer to 4-byte little endian hex string
# e.g. 800 => 0x320 => 00000320 (big-endian) =>20030000 (little-endian)
def i2LeHexStr(i):
be_hex = ('0000000'+hex(i)[2:])[-8:]
n = 2 # split every 2 letters
return ''.join([be_hex[i:i+n] for i in range(0, len(be_hex), n)][::-1])
BMP_HEADER = BMP_HEADER % (i2LeHexStr(len(aligned_pixels)/(BYTE/BPP)+BMP_HEADER_SIZE),i2LeHexStr(width),i2LeHexStr(height))
sys.stdout.write(Hex2Bytes(BMP_HEADER+aligned_pixels))
编辑:有关此电子纸显示的所有内容以及我在其上显示内容的代码,请访问:https://github.com/yy502/ePaperDisplay
答案 1 :(得分:0)
看看https://en.wikipedia.org/wiki/BMP_file_format#File_structure。 问题是您没有指定颜色表。根据维基百科文章,如果位深度小于8位,那么这些是强制性的。
答案 2 :(得分:0)
在解决问题方面做得很好。您还可以考虑为ImageMagick创建个人委托或自定义委托,以帮助自动化该过程。 ImageMagick能够将不能自己处理的格式委托给代理人或助手,例如你的2位助手; - )
您可以在/etc/ImageMagick/delegates.xml
中创建自己的代理,而不是干扰可能位于$HOME/.magick/delegates.xml
的系统范围代理。你的看起来像这样:
<?xml version="1.0" encoding="UTF-8"?>
<delegatemap>
<delegate encode="epaper" command="convert "%f" +matte -colors 4 -depth 8 -colorspace gray pgm:- | /usr/local/bin/4_level_gray_4bpp_BMP_converter.py > out.bmp"/>
</delegatemap>
然后如果你跑:
identify -list delegate
您会看到自己被列为&#34;已知&#34; 帮助者。
这意味着您将能够运行如下命令:
convert a.png epaper:
它将自动执行2位BMP操作。
答案 3 :(得分:0)
您可以使用此功能:
convert in.jpg -colorspace gray +matte -colors 2 -depth 1 -resize '640x384>' pgm:- > out.bmp**
答案 4 :(得分:0)
我也有这个电子纸显示器。经过反复试验,我能够使用以下命令使用ImageMagick正确转换图像:
convert -verbose INPUT.BMP -resize 300x300 -monochrome -colorspace sRGB -colors 2 -depth 1 BMP3:OUTPUT.BMP
答案 5 :(得分:0)
这适用于Imagemagick 6.9.10.23 Q16 Mac OSX Sierra
convert logo.png -colorspace gray -depth 2 -type truecolor logo_depth8_gray_rgb.bmp
http://www.fmwconcepts.com/misc_tests/logo_depth8_gray_rgb.bmp
添加-type truecolor可将图像转换为RGB,但按照-colorspace grey采用灰色调。深度2在直方图中仅创建4种颜色。