默认情况下,AddressSanitizer会将所有错误抛给shell本身,因此我尝试使用以下命令运行我的ASAN构建;
>MCTester_ASAN>asan.log
==15619==ERROR: AddressSanitizer: heap-buffer-overflow on address 0x61400000f9d0 at pc 0x46cff2 bp 0x7fffc062cb90 sp 0x7fffc062cb88
#0 0x46cff1 in heapOutOfBoundWrite() /home/MemTest/main.cpp:49
#1 0x46d68f in main /home/MemTest/main.cpp:116
#2 0x7fbd3365bc35 in __libc_start_main (/lib64/libc.so.6+0x1ec35)
#3 0x40a0f8 (/x01/exd10/bin/MCTester_ASAN+0x40a0f8)
ASAN:SIGSEGV
==15619==ERROR: AddressSanitizer: SEGV on unknown address 0x00000044ff97 (pc 0x00000046cff2 sp 0x7fffc062cba0 bp 0x7fffc062cbb0 T0)
#0 0x46cff1 in heapOutOfBoundWrite() /home/MemTest/main.cpp:49
#1 0x46d68f in main /home/MemTest/main.cpp:116
#2 0x7fbd3365bc35 in __libc_start_main (/lib64/libc.so.6+0x1ec35)
#3 0x40a0f8 (/x01/exd10/bin/MCTester_ASAN+0x40a0f8)
AddressSanitizer can not provide additional info.
Segmentation fault
但我仍然将输出发送到shell本身而不是日志文件。
如何将输出捕获到日志文件中?
答案 0 :(得分:3)
但我仍然将输出发送到shell本身而不是日志文件。
这是因为AddressSanitizer
将错误放在stderr中,而不放在stdout中。
你的问题有很多answers。
例如:
yourcommand &>filename
答案 1 :(得分:0)
要使消毒剂将报告写入文件,您可以将log_path=log_file
作为ASAN_OPTIONS
的一部分传递。如果您希望看到asan消息与其他任何输出分开的消息,它可能会很方便。注意:文件名将不完全是log_file
,而是log_file.$pid
。
示例:
$ cat test.cpp
int main() {
*((char*)0) = 0;
}
$ g++ test.cpp -o a -fsanitize=address -g3
$ ASAN_OPTIONS="log_path=asan.log" ./a
AddressSanitizer:DEADLYSIGNAL
$ cat asan.log.436962
=================================================================
==436962==ERROR: AddressSanitizer: SEGV on unknown address 0x000000000000 (pc 0x5626d3a50196 bp 0x7ffd0b2c2b00 sp 0x7ffd0b2c2b00 T0)
==436962==The signal is caused by a WRITE memory access.
==436962==Hint: address points to the zero page.
#0 0x5626d3a50196 in main /tmp/test.cpp:2
#1 0x7f79c3a78151 in __libc_start_main (/usr/lib/libc.so.6+0x28151)
#2 0x5626d3a5008d in _start (/tmp/a+0x108d)
AddressSanitizer can not provide additional info.
SUMMARY: AddressSanitizer: SEGV /tmp/test.cpp:2 in main
==436962==ABORTING