我有一个表格,我想将其转换为XML格式。该表称为tempTable,并保存数据:
REF DESC QTY
100001 Normal 1
100002 OOH 1
我需要以这种给定的格式创建XML:
<row>
<LIN NUM="1">
<FLD NAME="REF">100001</FLD>
<FLD NAME="DES">Normal</FLD>
<FLD NAME="QTY">1</FLD>
</LIN>
<LIN NUM="2">
<FLD NAME="REF">100002</FLD>
<FLD NAME="DES">OOH</FLD>
<FLD NAME="QTY">1</FLD>
</LIN>
</row>
我尝试过以下代码:
SET @line = (SELECT '1' AS '@NUM', REF AS 'REF', DES AS 'DES', QTY AS 'QTY' FROM tempTable WHERE ORDER= @ORDER
FOR XML PATH('LIN'))
SELECT @line
FOR XML PATH
但是这会产生:
<row>
<LIN NUM="1">
<REF>100001</REF>
<DES>Normal</DES>
<QTY>1</QTY>
</LIN>
<LIN NUM="1">
<REF>100002</REF>
<DES>OOH</DES>
<QTY>1</QTY>
</LIN>
</row>
有谁知道我怎么做:
B)将“名称”属性添加到“LIN”详细信息并更改 字段名称为'FLD'。当我尝试将名称更改为“FLD”时 将值汇总到单个节点上,如下所示:
<row>
<LIN NUM="1">
<FLD>100001Normal1</FLD>
</LIN>
<LIN NUM="1">
<FLD>100002OOH1</FLD>
</LIN>
</row>
我假设我可以添加'NAME'属性来分隔值吗?
非常感谢任何建议/帮助。
由于
答案 0 :(得分:5)
declare @tempTable table (Ref int, Des varchar(100), Qty int)
insert into @tempTable values (100001, 'Normal', 1), (100002, 'OOH', 1)
SELECT ROW_NUMBER() OVER (ORDER BY Ref) AS '@NUM',
'REF' AS 'FLD/@NAME', REF AS 'FLD', '',
'DES' AS 'FLD/@NAME', DES AS 'FLD', '',
'QTY' AS 'FLD/@NAME', QTY AS 'FLD'
FROM @tempTable
FOR XML PATH('LIN'), ROOT ('row')
产生
<row>
<LIN NUM="1">
<FLD NAME="REF">100001</FLD>
<FLD NAME="DES">Normal</FLD>
<FLD NAME="QTY">1</FLD>
</LIN>
<LIN NUM="2">
<FLD NAME="REF">100002</FLD>
<FLD NAME="DES">OOH</FLD>
<FLD NAME="QTY">1</FLD>
</LIN>
</row>
在https://stackoverflow.com/a/25412657/4473405的帮助下,因为如果节点和select中的属性之间没有空字符串,SQL Server会给出错误:
以属性为中心的列'FLD / @ NAME'不得位于FOR XML PATH中XML层次结构中非属性中心的兄弟之后。
编辑:正如评论中所提到的,this post解释了为什么空引用技巧有效。
总结:
FOR XML PATH
中,没有名称的列成为文本节点
NULL
或''
因此成为空文本节点AS *
答案 1 :(得分:0)
DECLARE @t TABLE (ref varchar(10), descr varchar(10), qty varchar(3))
insert into @t
values('100001', 'Normal', '1'),('10002','OOH','1')
SELECT ROW_NUMBER() OVER (ORDER BY a.ref) AS '@NUM',
(SELECT 'REF' AS 'FLD/@NAME'
,ref AS 'FLD'
FROM @t AS FLD
WHERE FLD.ref = a.ref
FOR XML PATH(''), TYPE),
(SELECT 'DESCR' AS 'FLD/@DESCR'
,descr AS 'FLD'
FROM @t AS FLD
WHERE FLD.ref = a.ref
FOR XML PATH(''), TYPE),
(SELECT 'QTY' AS 'FLD/@QTY'
,QTY AS 'FLD'
FROM @t AS FLD
WHERE FLD.ref = a.ref
FOR XML PATH(''), TYPE)
FROM @t AS a
FOR XML PATH('LIN'), ROOT('row')