Question

如何获取条件名称为＆＃34; task1＆＃34;，value =＆＃34; abc＆＃34; AND name =＆＃34; task2＆＃34;，value =＆＃34; efg＆＃34; name =＆＃34; task5＆＃34;，value =＆＃34; nop＆＃34;

预期产出：ABC-123; XYZ-987
实际输出：XYZ-987
查询：/node1/node2/node3[condition/task[@name='task1' and @value='abc'] and condition/task[@name='task2' and @value='efg'] and condition/task[@name='task5' and @value='nop'] and count(condition/task)=3]/id

来自How to parse and fetch exact result from XML using XPATH

的查询

Catch 如果任务中的所有操作（满足任务除外）都是＆＃34; OR＆＃34;那么该ID也应被视为满意条件。在下面的XML中，ABC-123，LMN-543和XYZ-987满足条件，但ABC-123具有所有其他操作=＆＃34; OR＆＃34;。所以这也应该包含在结果中。通过使用计数，我限制为3个任务，因此不包括ABC-123。使用count> 3将获取ABC-123，LMN-543和XYZ-9876。

需要输出为ABC-123; XYZ-987 使用条件检查操作=或

以下是使用的XML

<node1>
<node2>
    <node3>
        <id>ABC-123</id>
        <condition>
            <task name="task1" operation="and" value="abc" />
            <task name="task2" operation="and" value="efg" />
            <task name="task3" operation="or" value="hij" />
            <task name="task4" operation="or" value="klm" />
            <task name="task5" operation="or" value="nop" />
            <task name="task6" value="uvw" />
        </condition>
    </node3>
    <node3>
        <id>LMN-543</id>
        <condition>
            <task name="task1" operation="and" value="abc" />
            <task name="task2" operation="and" value="efg" />
            <task name="task3" operation="and" value="hij" />
            <task name="task4" operation="or" value="klm" />
            <task name="task5" operation="or" value="nop" />
            <task name="task6" value="uvw" />
        </condition>
    </node3>
    <node3>
        <id>XYZ-987</id>
        <condition>
            <task name="task1" operation="and" value="abc" />
            <task name="task2" operation="and" value="efg" />
            <task name="task5" operation="or" value="nop" />
        </condition>
    </node3>
    <node3>
        <id>RST-567</id>
        <condition>
            <task name="task1" operation="and" value="abc" />
            <task name="task2" operation="and" value="efg" />
            <task name="task8" operation="and" value="jkl" />
            <task name="task9" operation="and" value="rst" />
            <task name="task10" value="xyz" />
        </condition>
    </node3>
    <node3>
        <id>PQR-345</id>
        <condition>
            <task name="task1" operation="and" value="ijk" />
            <task name="task2" operation="and" value="klm" />
            <task name="task8" operation="and" value="jkl" />
            <task name="task9" operation="and" value="rst" />
        </condition>
    </node3>
</node2>
</node1>

Answer 1

你必须重新构建你的条件：

/node1/node2/node3[(condition/task/@name='task1' and condition/task/@value='abc') and (condition/task/@name='task2' and condition/task/@value='efg')  and (condition/task/@name='task5' and condition/task/@value='nop')]/id

在这种情况下，圆括号（）是可选的，但它们提高了可读性。请注意，根据您提供的示例数据，LMN-543也满足查询。

返回

<id>ABC-123</id>
<id>LMN-543</id>
<id>XYZ-987</id>

我对你的'捕捉'条件不太清楚，但根据你所说的，它可以在每个节点中翻译，最多有2个操作=“和”任务。这使得和其他

and (count(condition/task[@operation='and']) < 3)

所以xpath成为

/node1/node2/node3[(condition/task/@name='task1' and condition/task/@value='abc') and (condition/task/@name='task2' and condition/task/@value='efg')  and (condition/task/@name='task5' and condition/task/@value='nop') and (count(condition/task[@operation='and']) < 3)]/id

返回：

<id>ABC-123</id>
<id>XYZ-987</id>

Answer 2

/node1/node2/node3[count(condition/task[not(@name='task1' and @value='abc') and not(@name='task2' and @value='efg') and @operation]) = count(condition/task[@operation='or'])]/id

将返回所有ID：

具有@operation属性且未与条件@name='task1' and @value='abc'和@name='task2' and @value='efg'
等于@operation = 'or'

是ABC-123和XYZ-987

XPATH解析复杂数据的问题

2 个答案: