Question

编写一个以整数作为输入参数并返回的函数使用单词的整数。例如，如果输入是4721那么函数应该返回字符串＆＃34;四个七二一＆＃34;。注意这些单词之间应该只有一个空格，它们应该是所有在你返回的字符串中小写。

这是我的代码：

def Numbers_To_Words (number):
    dict = {1: "one", 2: "two", 3: "three", 4: "four", 5: "five", 6: "six", 7: "seven", 8: "eight", 9: "nine", 0: "zero"}
    output_str = " "
    list = []

#Main Program
number = 4721
result = Numbers_To_Words (number)
print (result)

我的问题是，如何将数字分开，然后与我创建的字典进行比较？我知道长度不适用于整数数据类型。我知道将密钥发送到字典并获取其各自值的进一步逻辑。但在此之前，我被困在这里分隔整数的数字。

Answer 1

使用模块： https://pypi.python.org/pypi/num2words

另外，请检查类似的问题：How do I tell Python to convert integers into words

您可以安装模块，看看它是如何在那里实现的。

但你的问题解决了：

def Numbers_To_Words (number):
    dictionary = {'1': "one", '2': "two", '3': "three", '4': "four", '5': "five", '6': "six",
            '7': "seven", '8': "eight", '9': "nine", '0': "zero"}
    return " ".join(map(lambda x: dictionary[x], str(number)))


print Numbers_To_Words(1234)

Answer 2

有一种比其他方式更简单的方法：

def number_to_words(number)
    words = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten"]
    return " ".join(words[int(i)] for i in str(number))

Answer 3

def number_to_words(number):
    dict={"1":"one","2":"two","3":"three","4":"four","5":"five","6":"six","7":"seven","8":"eight","9":"nine","0":"zero"}
    s=""
    for c in str(number):
        s+=dict[c]+" "
    #if it's matter that the string won't conatain
    #space at the end then add the next line:
    s=s[:-1]

    return s

Answer 4

我会使用re.sub

>>> def Numbers_To_Words (number):
    dict_ = {'1': "one", '2': "two", '3': "three", '4': "four", '5': "five", '6': "six", '7': "seven", '8': "eight", '9': "nine", '0': "zero"}
    return re.sub(r'\d', lambda m: dict_[m.group()] + ' ', str(number)).strip()

>>> print Numbers_To_Words(4721)
four seven two one
>>> print Numbers_To_Words(98765423)
nine eight seven six five four two three

Answer 5

def number_to_words(number):
    names = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
    lst = []
    while True:
        lst.insert(0, number % 10) # Prepend
        number /= 10
        if number == 0:    # Do this here rather than in the while condition
           break;          # so that 0 results in ["zero"]

    # If you want a list, then:
    return lst;

    # If you want a string, then:
    return " ".join(lst)

Answer 6

这将帮助您在无法导入用于将数字转换为单词的模块的地方。该代码用于将数字从1转换为1000（包括两个数字）。

["sea",                # User's search term
  ["sears",            # Suggested search terms
   "search engines",
   "search engine",
   "search",
   "sears.com",
   "seattle times"],
  ["7,390,000 results",    # Suggested search descriptions
   "17,900,000 results",
   "25,700,000 results",
   "1,220,000,000 results",
   "1 result",
   "17,600,000 results"],
  ["http://example.com?q=sears",  # Links for suggested searches (optional)
   "http://example.com?q=search+engines",
   "http://example.com?q=search+engine",
   "http://example.com?q=search",
   "http://example.com?q=sears.com",
   "http://example.com?q=seattle+times"]]

如何将整数转换为python中的单词？

6 个答案: