看哪

Question

我想从支持bean中的xhtml获取强度指标。如果＆＃34;指标＆＃34;弱者说，我会做一些行动。

现在这是我的xhtml代码

        <h:form id="changePasswordForm"  >
        <p:messages id="changePasswordMessages" />
        <h:panelGrid columns="3" >  
            <h:outputText for="oldPassword" value="CurrentPassword" />  
            <p:password id="oldPassword" value="#{changePasswordBean.oldPassword}" 
                label="CurrentPassword" required="true" feedback="false" minLength="6" />
            <p:message for="oldPassword" display="icon" />

            <p:spacer height="4px" />
            <p:spacer height="4px" />
            <p:spacer height="4px" />

            <h:outputText for="newPassword1" value="#{NewPassword}" />  
            <p:password id="newPassword1" value="#{changePasswordBean.newPassword1}" 
                label="NewPassword" required="true" feedback="true" minLength="6" match="newPassword2"/>
            <p:message for="newPassword1" display="icon" />  

            <h:outputText for="newPassword2" value="#{ConfirmPassword}" />  
            <p:password id="newPassword2" value="#{changePasswordBean.newPassword2}" 
                label="ConfirmPassword" required="true" feedback="true" minLength="6" />
            <p:message for="newPassword2" display="icon" />
        </h:panelGrid>

        <table style="border:0; width:100%;">
            <tr>
                <td colspan="2">
                    <p:separator style="margin:0;" />
                </td>
            </tr>
            <tr>
                <td class="input" style="width:50%;">
                    <p:commandButton value="#{Save}"
                        process=":changePasswordForm" 
update=":changePasswordForm"
    actionListener="#{changePasswordBean.save()
                        icon="ui-icon-disk" />
                </td>
            </tr>
        </table>
    </h:form>

现在的问题是，我不知道如何得到弱势＆＃34;或者强大的＆＃34;来自支持bean中的UI的消息。有人可以帮帮我吗？

我使用的是JSF 2和PrimeFaces 3.4。

Answer 1

看哪

将JavaScript实现转换为Java。

来源

public class PasswordValidator implements Serializable {

    /**
     * Less than this is weak, more that this is good.
     */
    public final static int MEDIUM = 30;
    /**
     * More than this is strong.
     */
    public final static int STRONG = 80;

    private String password;
    private int score;

    public PasswordValidator() {
    }

    public PasswordValidator(String password) {
        setPassword(password);
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
        validatePassword();
    }

    private void validatePassword() {
        score = testStrength(password);
    }

    public int getScore() {
        return score;
    }

    public boolean isWeak() {
        return score <= MEDIUM;
    }

    public boolean isAtLeastGood() {
        return score >= MEDIUM;
    }

    public boolean isStrong() {
        return score >= STRONG;
    }

    public boolean isSecure() {
        return score == 100;
    }

    public static int testStrength(String d) {
        if (d == null || d.isEmpty())
            return 0;
        //var b=0,c=0,a=this;
        float b = 0;
        int c;
        //c=d.match("[0-9]");b+=a.normalize(c?c.length:1/4,1)*25; 
        c = countMatches(d, "[0-9]"); // asks for at least one number
        b += normalize(c != 0 ? 1 : 1 / 4F, 1) * 25;
        //c=d.match("[a-zA-Z]");b+=a.normalize(c?c.length:1/2,3)*10; 
        c = countMatches(d, "[a-zA-Z]"); // matches only latin characters, not other character sets
        b += normalize(c != 0 ? 1 : 1 / 2F, 3) * 10;
        //c=d.match("[!@#$%^&*?_~.,;=]");b+=a.normalize(c?c.length:1/6,1)*35; 
        c = countMatches(d, "[!@#$%^&*?_~.,;=]"); // asks for at least on symbol
        b += normalize(c != 0 ? 1 : 1 / 6F, 1) * 35;
        //c=d.match("[A-Z]");b+=a.normalize(c?c.length:1/6,1)*30; 
        c = countMatches(d, "[A-Z]"); // asks for at least one capital letter
        b += normalize(c != 0 ? 1 : 1 / 6F, 1) * 30;
        //b*=d.length/8;
        b *= d.length() / 8F;
        System.out.println(b);
        //return b>100?100:b  
        return b > 100 ? 100 : (int) b;
    }

    private static float normalize(float a, float c) {
        return a - c <= 0 ? a / c : 1 + 0.5F * (a / (a + c / 4));
    }

    private static int countMatches(String container, String regex) {
        int i = 0;
        Matcher m = Pattern.compile(regex).matcher(container);
        while (m.find())
            i++;
        return i;
    }

}

用法

PasswordValidator.testStrength("password"); // e.g. 83
// or
PasswordValidator pv = new PasswordValidator(); // or new PasswordValidator("password")
pv.setPassword("password");
pv.getScore(); // e.g. 83
pv.isAtLeastGood(); // e.g. true
pv.isStrong(); // e.g. true

测试

JavaScript / PrimeFaces实施和我的密码强度得分结果。

Password          My class  PrimeFaces   
123456            28        28.125
Ofar-E*Qnmcm_eSPA 100       100
123456789aZ       88        88.22916666666666
2010.11.02        83        83.33333333333334
mississDOGippi    79        79.47916666666666

完美作品!!!

备注

PrimeFaces密码组件将包含31个字母（没有大写字母，数字或符号）的密码视为强密码，但这不是真的。
要测试PrimeFaces组件，请执行PrimeFaces.widget.Password.prototype.testStrength(PF('password-widget-var').jq.val())
要获取javascript函数的代码，请执行PrimeFaces.widget.Password.prototype.testStrength和PrimeFaces.widget.Password.prototype.normalize

PrimeFaces.widget.Password.prototype.testStrength

的源代码

function (d){
    var b=0, c=0, a=this;
    c=d.match("[0-9]");             b+=a.normalize(c?c.length:1/4,1)*25; 
    c=d.match("[a-zA-Z]");          b+=a.normalize(c?c.length:1/2,3)*10;
    c=d.match("[!@#$%^&*?_~.,;=]"); b+=a.normalize(c?c.length:1/6,1)*35;
    c=d.match("[A-Z]");             b+=a.normalize(c?c.length:1/6,1)*30;
    b*=d.length/8;
    return b>100?100:b
}

PrimeFaces.widget.Password.prototype.normalize

的源代码

function (a,c){var b=a-c;if(b<=0){return a/c}else{return 1+0.5*(a/(a+c/4))}}

没有理由在Java中使用float类型得分，所以我使用了整数。
两种实现都接受仅拉丁字符集。

（再次）作品完美!!!

因此，您在后端所要做的就是将密码传递给PasswordValidator，您将获得其强度，这与PrimeFaces计算的值相同。要计算密码是否弱，PrimeFaces计算的好或强使用PasswordValidator的相应方法。

如何从支持bean

1 个答案:

看哪

来源

用法

测试

备注