我是ajax和jquery的新手,所以我想请你们帮忙。我需要创建新用户的表单,然后记录用户。 这些函数很有用,但是我想为函数的成功或失败创建警告框。
我不知道如何......这是我的代码
HTML
<!-- Formular for signing up -->
<h4 class="form-headline"> Not a member? Sign up here </h4>
<form method="post">
<div class="form-group">
<label> Username </label>
<input type="text" class="form-control" id="newusername">
</div>
<div class="form-group">
<label> Password </label>
<input type="password" class="form-control" id="newpassword">
</div>
<div class="form-group">
<label> Your club </label>
<input type="text" class="form-control" id="newclub">
</div>
<input type="button" id="btn-reg" class="btn btn-success" value="Sign up!">
</form>
脚本
// -----------------Registration of new user----------------------
console.log('Script loaded...');
// Calling for the method - reg
$("#btn-reg").on("click", reg);
function reg(e) {
e.preventDefault();
console.log('Klick, klick...');
// Declaring variables
var newusername=$("#newusername").val();
var newpassword=$("#newpassword").val();
var newclub=$("#newclub").val();
$.post('classCalling.php', {
newusername: newusername,
newpassword: newpassword,
newclub: newclub
},
function(data){
console.log(data);
});
}
PHP
// Creating instance of the class userClass.php
var_dump($_POST);
if(isset($_POST['newusername'])){
// Defining variables
$newusername = $_POST['newusername'];
$newpassword = $_POST['newpassword'];
$newclub = $_POST['newclub'];
// Password hash
$hashpassword = sha1($newpassword);
$user = new User();
$user->newUsers($newusername, $hashpassword, $newclub);
} else {
}?>
OOP
// >>>>>>>>>>>>>>>> Function for saving new user to database
public function newUsers($newusername, $hashpassword, $newclub) {
// Using prepared statement to prevent mysql injections.
$stmt = $this->db->prepare("INSERT INTO users(username, password, club)VALUES(?, ?, ?);");
$stmt->bind_param("sss", $newusername, $hashpassword, $newclub);
if($stmt->execute()) {
echo "<h3 class='usercreated'>Created</h3>";
} else {
echo "<h3 class='usercreated'> Failed </h3>";
}
}
答案 0 :(得分:0)
您可以回显脚本标记。
if($stmt->execute()) {
echo "<h3 class='usercreated'>Created</h3>";
echo "<script type="text/javascript">";
echo "alert("Hello World!")";
echo "</script>";
} else {
echo "<h3 class='usercreated'> Failed </h3>";
echo "<script type="text/javascript">";
echo "alert("Hello World!")";
echo "</script>";
}
}
答案 1 :(得分:0)
刚刚注意到你正在使用函数来创建一个新用户,我的又坏了
if(isset($_POST['newusername'])){
// Defining variables
$newusername = $_POST['newusername'];
$newpassword = $_POST['newpassword'];
$newclub = $_POST['newclub'];
// Password hash
$hashpassword = sha1($newpassword);
$user = new User();
$status = $user->newUsers($newusername, $hashpassword, $newclub);
if($status) {
echo json_encode(array("status" : "success"));
}else {
echo json_encode(array("status" : "failed"));
}
}
从此功能返回
public function newUsers($newusername, $hashpassword, $newclub) {
// Using prepared statement to prevent mysql injections.
$stmt = $this->db->prepare("INSERT INTO users(username, password, club)VALUES(?, ?, ?);");
$stmt->bind_param("sss", $newusername, $hashpassword, $newclub);
if($stmt->execute()) {
return true;
}else {
return false
}
}
这将是相同的
$.post('classCalling.php', {
newusername: newusername,
newpassword: newpassword,
newclub: newclub
},
function(data){
var object = JSON.parse(data);
alert(object.status);
// or you can add if else by using the status
});
}
答案 2 :(得分:0)
对于脚本块。
var posting = $.post('classCalling.php', {
newusername: newusername,
newpassword: newpassword,
newclub: newclub
});
posting.done(function( data ) {
alert( "Data Loaded Ok");
});
posting.fail(function( data ) {
alert( "Error loading data");
});
希望这会对你有所帮助。