Question

我试图制作一个项目，询问有关酒店访问的一些问题并重复回答，非常简单。到目前为止，我有这个代码：

#include<iostream>
#include<string>
using namespace std;

int main()
{
    int df;
    int days; 
    string bed;
    string bn;

    cout << "Welcome to C++ Hotel, we have to ask you a few questions about your stay in order to give you the correct rate." << endl;
    cout << "First, what floor would you like to stay on? (We currently have rooms available from floors 2 to 12)" << endl;
    cin >> df;
    while (df > 12 && 2 < df){
        cout << "Sorry, but your answer is invalid, please enter a floor from 2 to 12." << endl;
        cin >> df;
    }
    cout << "Okay, we will register your room on floor " << df << "." << endl;
    cout << "Now, what type of bed will you be requesting during your visit? On floor " << df << " we currently have doubles, queens, or a suite." << endl;
    cin >> bed;
    while (bed != "d" && bed != "q" && bed != "s"){
        cout << "Sorry, but your answer is invalid, please choose between a double, queen or suite by entering either d, q, or s respectively." << endl;
        cin >> bed;
    } 

    if (bed == "d"){
        string bn = "double";
    } 
    if (bed == "q"){
        string bn = "queen";
    }
    if (bed == "s"){
        string bn = "suite";
    }
    cout << "Okay, your room will be on floor " << df << " with a " << bn << "     sized bed!" << endl;
}

我希望用户能够为双人，女王或套房床尺寸选项输入d，q或s，但我也想重复他们在问题末尾所选择的内容，这显然听起来很愚蠢如果它说的是＆＃34;你已经选择了d尺寸的床！＆＃34;

所以我做了一些if语句，基本上根据用户输入的原始床变量设置了一个新的字符串变量。因此，如果他们输入d为double，则bn变量设置为＆＃34; double＆＃34;，然后在最后cout中调用bn。

然而，代码似乎只是完全跳过了3个if语句，并且当调用变量时它只是空白，代码运行良好，没有错误或警告或任何东西，但我可以＆＃39 ;弄清楚为什么它不能识别代码，对我来说似乎没问题？

Answer 1

将string bn = "double";替换为

bn = "double";

您要声明另一个名为string的本地bn并将其设置为某个值，并且您要设置的实际bn保持不变。

进一步阅读：Scope in C++

为什么这段代码会跳过设置字符串变量的if语句？

1 个答案: