Question

我将字符串{"abc":"dds","def":null,"ghi":fgi"}存储在数据库的字段中。如何在＆＃34; def＆＃34;之后找到下一个逗号。字符串？

其实我有这样的字符串列表，例如

{"abc":"dds","def":null,"ghi":"fgi"}
{"abc":"123","def":234,"ghi":"fgd"}
{"abc":"133-d","def":"asd-123","ghi":"fgi"}
.....

我需要删除所有出现的＆＃34; def＆＃34;有价值的，我需要结果为

{"abc":"dds","ghi":"fgi"}
{"abc":"123","ghi":"fgd"}
{"abc":"133-d","ghi":"fgi"}

Answer 1

我根据您提供的数据给您一个工作示例。

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SET @str := '{"abc":"133-d","def":"asd-123","ghi":"fgi"}';

Demo Here

<强>解释

SELECT CONCAT( SUBSTRING( @str FROM 1 FOR LOCATE('def' ,@str) - 2 ), SUBSTRING( @str FROM (LOCATE('def' ,@str) + LOCATE(',',SUBSTRING(@str,LOCATE('def' ,@str)))) FOR (LENGTH(@str) + 1 - (LOCATE('def' ,@str) + LOCATE(',',SUBSTRING(@str,LOCATE('def' ,@str))))) ) ) AS newJson;

Explanation based on this string '{"abc":"dds","def":null,"ghi":fgi"}'

现在连续结果＃1和结果＃4得到完整的所需字符串{“abc”：“dds”，“ghi”：fgi“}

注意：在应用程序级别执行此作业肯定会为您提供更大的灵活性。

修改

您可以创建一个名为SELECT SUBSTRING(@str FROM 1 FOR LOCATE('def' ,@str) - 2 ); Result#1: {"abc":"dds", SELECT (LOCATE('def' ,@str) + LOCATE(',',SUBSTRING(@str,LOCATE('def' ,@str)))); Result#2: 25 // Location of the comma next to 'def':value SELECT (LENGTH(@str) + 1 - (LOCATE('def' ,@str) + LOCATE(',',SUBSTRING(@str,LOCATE('def' ,@str))))); Result#3: 11 // Length of the rest of the string after that very comma Now get the SUBSTRING(@str FROM position 25 to Result#3 ) It will return Result #4: "ghi":fgi"}的函数，并在需要的地方使用它。

getNewJsonString

示例函数调用：

DELIMITER $ DROP FUNCTION IF EXISTS getNewJsonString$ CREATE FUNCTION getNewJsonString(inputStr VARCHAR(300)) RETURNS VARCHAR(255) READS SQL DATA BEGIN DECLARE returnString VARCHAR(255); SET @str := inputStr; SET returnString := (SELECT CONCAT( SUBSTRING( @str FROM 1 FOR LOCATE('def' ,@str) - 2 ), SUBSTRING( @str FROM (LOCATE('def' ,@str) + LOCATE(',',SUBSTRING(@str,LOCATE('def' ,@str)))) FOR (LENGTH(@str) + 1 - (LOCATE('def' ,@str) + LOCATE(',',SUBSTRING(@str,LOCATE('def' ,@str))))) ) )) ; RETURN returnString; END$ DELIMITER ;

<强>输出：

SELECT getNewJsonString('{"abc":"dds","def":null,"ghi":"fgi"}');

找到字符串中给定子字符串的下一个逗号

1 个答案: